Question

At a basketball game, members of the Spirit Club use a t-shirt cannon to launch team t-shirts to spectators in the stands. The equation below describes the height, h, of the t-shirt, t seconds after it is shot from the cannon c feet above the ground, at an initial velocity of v. h = -16t 2 + vt + c Solve the equation for initial velocity, v.

Answer 1

The initial velocity is 90 ft/sec 

Answer 2

Answer:

The required equation is $v=\frac{h-c+16t^2}{t}$.

Step-by-step explanation:

The given equation is

$h=-16t^2+vt+c$

where h is height of t-shirt after t seconds, c is initial height and v is initial velocity.

We have to solve the equation for initial velocity, v.

Subtract c from both the sides.

$h-c=-16t^2+vt$

Add 16t² on both the sides.

$h-c+16t^2=vt$

Divide both sides by t.

$\frac{h-c+16t^2}{t}=v$

Therefore the required equation is $v=\frac{h-c+16t^2}{t}$.