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Rasek [7]
3 years ago
14

What is the 45th term of the sequence generated by the formula (-1) 2n+1 ?

Mathematics
1 answer:
Natalija [7]3 years ago
5 0

Answer:

−0.989010989010

Step-by-step explanation:

what is the 45th term of a sequence generated by the formula tn=(-1)^n * (2n/2n+1)?

When n= 45

tn=(-1)^n*(2n/2n+1)

tn = (-1)^45 * ( 2(45) / 2(45) + 1

= -1 * 90 / (90+1)

= -90 / 91

= −0.989010989010

The 45th term of the sequence generated by the formula tn=(-1)^n*(2n/2n+1) is −0.989010989010

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Read 2 more answers
The amount ofmoney is in the ratio 8:3 if the first amount is 9.92 what is the second amount?
BARSIC [14]

Answer:

The second amount is 3.72

Step-by-step explanation:

Given

First : Second = 8 : 3

First = 9.92

Required

Find Second

First : Second = 8 : 3

Substitute 9.92 for First

9.92: Second = 8 : 3

Express as fraction

\frac{Second}{9.92} = \frac{3}{8}

Multiply both sides by 9.92

9.92 * \frac{Second}{9.92} = \frac{3}{8}*9.92

Second = \frac{3}{8}*9.92

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5 0
3 years ago
A researcher computes the following 2 x 3 between-subjects ANOVA, in which 11 participants were observed in each group. Which ef
pishuonlain [190]

Answer:

D. There were no significant effects.

Step-by-step explanation:

The table below shows the representation of the significance level using the two-way between subjects ANOVA.

Source of Variation            SS          df          MS          F                P-value

Factor A                             10          1              10           0.21           0.660

Factor B                             50         2             25          0.52          0.6235  

     

A × B                                  40          2             20         0.42           0.6783

Error                                   240        5             48           -               -

Total                                   340       10             -             -                  -

From the table above , the SS(B) is determined as follows:

SS(B) = SS(Total)-SS(Error-(A×B)-A)

         =  340-(240-40-10)

         = 50

A researcher computes the following 2 x 3 between-subjects ANOVA;

k=2

n=3

N(total) = no of participants observed in each group =11

df for Factor A= (k-1)

=(2-1)

=1

df for Factor B = (n-1)

=(3-1)

=2

df for A × B    

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df  factor for total

=(N-1)

=11-1

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MS = SS/df

Thus, from the table, the P-Value for all data is greater than 0.05, therefore we fail to reject H₀.

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2 years ago
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