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iragen [17]
3 years ago
12

convert given per cents to decimal fraction and also to fractions to simplest form: 25 per cent PLZZ HELP​

Mathematics
1 answer:
love history [14]3 years ago
3 0

<em>Your answer is in the above Attachment </em>

<em>Your answer is in the above Attachment Hope It helps :)</em>

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A shelf has different sizes of bottles of laundry detergent. This line plot shows the number of cups of laundry detergent in eac
salantis [7]

Answer:

2 / 3 loads

Step-by-step explanation:

From. The plot, we can conclude that, the detergent that has the most bottles is that with 5 ; the number of cups in the detergent with 5 bottles is 12 cups

Number of cups used for each load of laundry = 18 cups

The loads of laundry Eric can do is thus :

Number of cups of detergent / number of cups used for each load of laundry

= 12 / 18

= 2 / 3 loads

8 0
3 years ago
Brainliest for best answer. No stupid answers please!
gladu [14]

Answer:

They both have the same slope.

They have different y- intercepts.

They have no solution.

Please let me know, if I am right or wrong. I try my best to give correct answers

3 0
3 years ago
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Solve for x:<br><br> 11x = 6x + 20
notka56 [123]

Answer:

x = 4

Step-by-step explanation:

11x= 6x +20

-6x   -6x

(subtract 6x from both sides)

5x = 20

/5x   /5x

divide 5x from both sides

x=4

3 0
3 years ago
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WILL GIVE BRAINLIEST PLEASE ANSWER ASAP
Wittaler [7]

Answer:

Circle man ez

Step-by-step explanation:

5 0
3 years ago
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Write three ordered pairs for direct variation relationship where y= 12 when x= 16
Kruka [31]

Ordered pairs that work for this direct variation are (4, 3), (8, 6) and (12, 9).

In order to find these, we must first find the value of the direct variation coefficient. We can do that using the base equation y = kx and then by plugging in to find k.

y = kx

12 = k(16)

3/4 = k

Now that we have k, we can model the equation as y = 3/4x. We can also find any number of ordered pairs by using the x value and finding the y value. All of the above answers work.

3 0
3 years ago
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