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Dmitriy789 [7]
3 years ago
10

Evaluate 6j+23+kl−3, when j=3, k=7, and l=33.

Mathematics
1 answer:
Dmitry [639]3 years ago
3 0

Answer:

269

Step-by-step explanation:

6(3)+23+(7)(33)-3

 \/              \/

18 + 23 + 231 - 3 = 269


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In a survey sample of 83 respondents, the mean number of hours worked per week is 39.04, with a standard deviation of 11.51. Cal
soldier1979 [14.2K]

Given that,

Sample size= 83

Mean number= 39.04

Standard deviation= 11.51

We know the critical t-value for  95% confidence interval which is equal to 1.989.

We also know the formula for confidence interval,

CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))

So, we have

CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)

CI= (39.04 - 2.513,39.04 + 2.513)

CI= (36.527,41.553)

Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).

8 0
3 years ago
Read 2 more answers
A. Complete the table if y varies
serious [3.7K]

Direct variation is represented by the equation y = k × x and inverse variation is represented by y = k/x

Table 1:

y = k × x

30 = k × 5

30 = 5k

k = 30/5

k = 6

So,

<em>y = 30 </em>

<em>y = 30 k = 6</em>

<em>y = 30 k = 6x = 5</em>

<em>y = 30 k = 6x = 5Equation: y = 6x</em>

y = k × x

y = 10 × 8

y = 80

So,

<em>y = 80 </em>

<em>y = 80 k = 10</em>

<em>y = 80 k = 10x = 8</em>

<em>y = 80 k = 10x = 8Equation: y = 10x</em>

y = 3x

18 = 3x

x = 18/3

x = 6

So,

<em>y = 18</em>

<em>y = 18k = 3</em>

<em>y = 18k = 3x = 6</em>

<em>y = 18k = 3x = 6Equation: y = 3x</em>

y = 2x²

72 = 2x²

x² = 72/2

x² = 36

x = √36

x = 6

So,

<em>y = 72</em>

<em>y = 72k = 2</em>

<em>y = 72k = 2x = 6</em>

<em>y = 72k = 2x = 6Equation: y = 2x²</em>

Table 2:

y = k/x

5 = k/6

5 × 6 = k

30 = k

So,

<em>y = 5</em>

<em>y = 5k = 30</em>

<em>y = 5k = 30x = 6</em>

<em>y = 5k = 30x = 6Equation: y = 30/x</em>

y = k/x

y = 36/4

y = 9

So,

<em>y = 9</em>

<em>y = 9k = 36</em>

<em>y = 9k = 36x = 4</em>

<em>y = 9k = 36x = 4Equation: y = 36/x</em>

y = 60/x

20 = 60/x

20x = 60

x = 60/20

x = 3

So,

<em>y = 20</em>

<em>y = 20k = 60</em>

<em>y = 20k = 60x = 3</em>

<em>y = 20k = 60x = 3Equation: y = 60/x</em>

y = 24/x

y = 24/12

y = 2

So,

<em>y = 2</em>

<em>y = 2k = 24</em>

<em>y = 2k = 24x = 12</em>

<em>y = 2k = 24x = 12Equation: y = 24/x</em>

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3 years ago
0.3(4-x)=x-1.4 how do you solve this problem?
tresset_1 [31]

Answer:

x = 2.

Step-by-step explanation:

Solve for x:

0.3 (4 - x) = x - 1.4

Expand out terms of the left hand side:

1.2 - 0.3 x = x - 1.4

Subtract x from both sides:

1.2 + (-0.3 x - x) = (x - x) - 1.4

-0.3 x - x = -1.3 x:

-1.3 x + 1.2 = (x - x) - 1.4

x - x = 0:

1.2 - 1.3 x = -1.4

Subtract 1.2` from both sides:

(1.2 - 1.2) - 1.3 x = -1.2 - 1.4

1.2 - 1.2 = 0:

-1.3 x = -1.2 - 1.4

-1.2 - 1.4 = -2.6:

-1.3 x = -2.6

Divide both sides of -1.3 x = -2.6 by -1.3:

(-1.3 x)/(-1.3) = (-2.6)/(-1.3)

(-1.3)/(-1.3) = 1:

x = (-2.6)/(-1.3)

(-2.6)/(-1.3) = 2.:

Answer:  x = 2.

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20 teachers selected sun rise beach. 12 teachers selected Mkapa bridge and St. Anthony's area. 16 teachers selected St.Anthony's
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Which triangles are similar? which theorem do you use to prove the similarity?​
AURORKA [14]
I think the similar triangle is d and b for this question
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