You know that the discrete metric only takes values of 1 and 0. Now suppose it comes from some norm ||.||. Then for any α in the underlying field of your vector space and x,y∈X, you must have that
∥α(x−y)∥=|α|∥x−y∥.
But now ||x−y|| is a fixed number and I can make α arbitrarily large and consequently the discrete metric does not come from any norm on X.
Step-by-step explanation:
hope this helps
Answer:
A. 5
Step-by-step explanation:
because 13 is the hypotenuse and 8 is the sine
Answer:
40/12 & 3 1/3
Step-by-step explanation:
honestly i can't give a good explanation, if the answer is not right, please someone comment, and i'll fix it.
Answer:
You can complete the mission 5 times before you earn less than 400 points.
Explanation:
