We're going to solve each of the systems to determine the solution.
<u>System 
</u>
using a graph tool
the solution is the line 
see the attached figure N
<u>System 
</u>
using a graph tool
the solution is the shaded area
see the attached figure N
<u>System 
</u>
using a graph tool
The system has no solution
see the attached figure N
<u>System 
</u>
using a graph tool
the solution is the shaded area
see the attached figure N
therefore
<u>the answer is</u>
<u>System </u>
Answer:
Step-by-step explanation:
CD is Pole
∠CAD = 4° {Alternate interior angles}
ΔCAD,
In ΔCDB,
∠B = 5° {Alternate interior angles}
Answer:
B) 6, 8, 10
Step-by-step explanation:
All right triangles will follow the following theorem (Pythagorean theorem):
, where 
and 
are two legs of the triangle and 
is the hypotenuse. Out of all answer choices, only B) 6, 8, 10 follow this theorem.
Answer:
x₂ = 7.9156
Step-by-step explanation:
Given the function ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ - f(xₙ)/f'(xₙ)
If f(x) = ln(x)+x-10
f'(x) = 1/x + 1
f(9) = ln9+9-10
f(9) = ln9- 1
f(9) = 2.1972 - 1
f(9) = 1.1972
f'(9) = 1/9 + 1
f'(9) = 10/9
f'(9) = 1.1111
x₁ = x₀ - f(x₀)/f'(x₀)
x₁ = 9 - 1.1972/1.1111
x₁ = 9 - 1.0775
x₁ = 7.9225
x₂ = x₁ - f(x₁)/f'(x₁)
x₂ = 7.9225 - f(7.9225)/f'(7.9225)
f(7.9225) = ln7.9225 + 7.9225 -10
f(7.9225) = 2.0697 + 7.9225 -10
f(7.9225) = 0.0078
f'(7.9225) = 1/7.9225 + 1
f'(7.9225) = 0.1262+1
f'(7.9225) = 1.1262
x₂ = 7.9225 - 0.0078/1.1262
x₂ = 7.9225 - 0.006926
x₂ = 7.9156
<em>Hence the approximate value of x₂ is 7.9156</em>
