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2 years ago

15

Explain the difference between a polygon that is regular and a polygon that is not regular

2 answers:

Sedbober [7]2 years ago

5 0

Regular polygons have equal sides

Irregular polygons have unequal sides

Fantom [35]2 years ago

3 0

Answer:

regular polygons have sides and interior angles that are the same and irregular polygons have sides and interior angles that are different

Step-by-step explanation:

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Tom has 7/8 gallons of paint. He used 1/2 gallon of paint on a project. He uses the steps to show how much paint he had when he

WINSTONCH [101]

He made his mistake in Step 2. Tom should have subtracted 4/8 instead of 1/8. The mistake is that he was not consistent when he multiplied Denominators (bottom number) must be the same when handling fractions so Tom must multiply both the numerator and denominator by the SAME number to balance it out. 1/2 x 4/4= 4/8. Subtract. 7/8 - 4/8= 3/8. Tom has 3/8 of a gallon of paint leftover.

4 0

3 years ago

Read 2 more answers

2^3 + 3(9-5) plz help

Romashka [77]

Answer:

The answer is 20

Step-by-step explanation:

6 0

2 years ago

Describe and correct the error in finding csc θ, given that θ is an acute angle of a right triangle and cos θ =7/11

a_sh-v [17]

Answer:

<h2>cosecθ = 1/sinθ = 11/6√2</h2>

Step-by-step explanation:

Given that cos θ =7/11, cosec θ = 1/sinθ in trigonometry.

Based on SOH, CAH, TOA;

cosθ = adjacent/hypotenuse = 7/11

adjacent = 7 and hyp = 11

Since sinθ = opp/hyp, we need to get the opposite to be able to calculate sinθ.

Using pythagoras theorem to get the opposite;

$hyp^{2} = adj^{2} + opp ^{2} \\opp = \sqrt{hyp^{2} - adj^{2} } \\opp = \sqrt{11^{2} - 7^{2}} \\opp = \sqrt{72} \\opp = 6\sqrt{2}$

sinθ = 6√2/11

cosecθ = 1/sinθ = 1/( 6√2/11)

cosecθ = 1/sinθ = 11/6√2

Note the error; cscθ $\neq$ 1/cosθ but cscθ = 1/sinθ

6 0

2 years ago

What is the simplest form of 2√2 / √3−√2

____ [38]

Answer:

A

Step-by-step explanation:

2√6 + 4

4 0

3 years ago

Read 2 more answers

Simplify the expression using trigonometric identities:

Anastaziya [24]

The simplified expression is the one in option B.

<h3>How to simplify the expression?</h3>

Remember that:

$sec(x) = 1/cos(x)\\\\cos(x) = cos(-x)$

With these two, we can rewrite the numerator as:

$sec(x)*sin(-x) + tan(-x)\\\\\frac{1}{cos(x)}*sin(-x) + tan(x)\\\\\frac{1}{cos(-x)}*sin(-x) + tan(-x)\\\\2*tan(-x)$

Replacing that in the given expression, we have:

$\frac{2*tan(-x)}{1 + sec(-x)} = \frac{2*tan(-x)}{1 + 1/cos(-x)}$

Now, if we multiply and divide by cos(-x), we get:

$\frac{2*tan(-x)}{1 + 1/cos(-x)} = \frac{2*tan(-x)}{1 + 1/cos(-x)}*\frac{cos(-x)}{cos(-x)} \\\\= \frac{2*sin(-x)}{1 + cos(-x)}$

Now remember that:

$cos(x) = cos(-x)\\sin(-x) = -sin(x)$

With these two properties:

$\frac{2*sin(-x)}{1 + cos(-x)} = \frac{-2*sin(x)}{1 + cos(x)}$

Then the correct option is B.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

#SPJ1

3 0

1 year ago