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Dmitry [639]
3 years ago
7

A figure is rotated and reflected. what can u say about the new figure in relation to the original figure?

Mathematics
1 answer:
mylen [45]3 years ago
8 0
The new figure is formed differently and is not the same as the other ome
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1) Find an equation of the tangent line at each given point on the curve.x = t2 − 4, y = t2 − 2tat (0, 0)at (−3, −1)at (−3, 3)2)
Anastasy [175]

Answer:

1) at ( 0,0) : y = x/2.   at(-3-1) : y = -1.   at(-3,3) : y = 2x +9

2) DNE ( does not exist )

Step-by-step explanation:

The general equation of tangent line

y - y1 = m( x - x1 )

attached below is the detailed solution on how i derived the answers above

8 0
4 years ago
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
Sarah opened new savings account on Tuesday with a deposit of $70. She made a deposit of $30 on Friday and a withdrawal of $60 o
irakobra [83]

Answer:

x=70+30-60

Step-by-step explanation:

Word to my mother

3 0
2 years ago
Can someone please answer this question I really need it?
Vlad [161]

Answer: the answer is A

Step-by-step explanation: i know this because i am a genius and you should listen to me

7 0
3 years ago
Read 2 more answers
What is 5d=470 and what is 8a=47
Igoryamba
5d=470:

in this case we have to divide both sides by 5:

d=94

8a=47:

in this case we have to divide both sides by 8:

a=5.875

as a general rule, if you want to find out a value of a in
ab=c

you have to divide both sides of the equation by b (if it's not zero); then you will have left:

a=c/b

and if you calculate c/b, this will give you the answer


8 0
3 years ago
Read 2 more answers
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