1/3 into a decimal is 0.333.....
It drops 32 feet each second so at six seconds it will have dropped 176 feet
Answer:
0.04,0.25.0.52
Step-by-step explanation:
Given that you throw a dart at a circular target of radius 10 inches.
Assuming that you hit the target and that the coordinates of the outcomes are chosen at random,
probability that the dart falls
(a) within 2 inches of the center
Here favourable region has area of a circle with radius 2 inches and sample space has area of 10 inches
Prob = 
(b) within 2 inches of the rim.
For within two inches from the rim we have to select area of the ring i.e. area of big circle with 10 inches - area of smaller circle with 10-2 inches
Prob= 
c) within I quadrant
area of I quadrant / area of circle=0.25
d) within I quadrant and within 2 inches of the rim
= I quadrant area + 2 inches ring area - common area
= 
Answer:
52.36%
Step-by-step explanation:
First you need to find the radius of the circle. You can do this by using the Pythagorean theorem, which states a^2+b^2=c^2. In this case a and b are equal to 1.2 and 1.6, and c is the radius of the circle. Plugging in we get 1.2^2+1.6^2=c^2 or 1.44+2.56=c^2 or 4=c^2. Finding the square root of both sides of the equation, we find that 2=c. Now that we have the radius, we can find the area of the circle. The area of a circle is expressed as πr^2, and plugging in 2 for r we get an area of 4π, or ~12.56637. Now all we do is divide 12,56637 by 24 and get what percentage of the area of the triangle the circle covers, which is roughly 0.5236, or 52.36%
The answer is 114 to your question