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Maksim231197 [3]
3 years ago
6

A new car sells for $30,000. The value of the car decreases by 16% annually. After how many years will the car be worth less tha

n $10,000.
a. after 2 years

b. after 6 years

c. after 8 years

d. not enough information

(answer c is incorrect)
Mathematics
1 answer:
DIA [1.3K]3 years ago
8 0

Answer: after 6 years.

Step-by-step explanation:

We would apply the formula for exponential decay which is expressed as

A = P(1 - r)^t

Where

A represents the value of the car after t years.

t represents the number of years.

P represents the initial value of the car.

r represents rate at which the value is decreasing.

From the information given,

P = 3000

A = < 10000

r = 16% = 16/100 = 0.16

Therefore

10000 = 30000(1 - 0.16)^ t

1000/30000 = (0.84)^t

0.333 = (0.84)^t

Taking log of both sides to base 10

Log 0.333 = log0.84^t = tlog0.84

- 0.4772 = t × - 0.0757

t = - 0.4772/ - 0.0757 = 6.3 years

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Studentka2010 [4]

Answer:

1000 times

Step-by-step explanation:

Given:

The Sun is roughly 10^2 times as wide as the Earth.

The Star KW Sagittarii is roughly 10^5 times as wide as the Earth.

Question asked:

About how many times as wide as the Sun is KW Sagittarii?

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\frac{x\times10^{5} }{x\times10^{2} }

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\frac{10^{5} }{10^{2} } =10^{5-2} =10^{3} =10\times\ 10\times10=1000

Therefore, Star  KW Sagittarii is 1000 times wider than Sun.

<em>First of all we calculated width of Sun in terms of width of earth and then calculated the width of the Star in terms of earth and for comparison we did simple division that showed that the Star KW Sagittarii is 1000 times wider than the Sun.</em>

<em />

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nata0808 [166]
4a + 2b = 10

you are solving for b

isolate the b

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Answer:

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Step-by-step explanation:

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