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brilliants [131]
3 years ago
7

Giving brainlist to whoever answers plz

Mathematics
2 answers:
ollegr [7]3 years ago
6 0

Answer:

It would be C

Step-by-step explanation:

-2 b +30 = 24 it would be right becase -2 + -2 - 30= 24

Elanso [62]3 years ago
5 0

Answer:

Okay! It should be the 3 one.

-2(3)+30=24

Step-by-step explanation:

You might be interested in
What congruence theorem tells us the two triangles are congruent if<br> any?
andriy [413]

Answer:

S.S.S is the correct answer

4 0
3 years ago
Simplify to create an equivalent expression. 8−4(−x+5)
White raven [17]
8 - 4(-x + 5)

As you already know, in order to find the equivalent expression to our already given one, we have to simplify it first :)

8 +4x - 20

**Remember that a negative times a negative is always a positive!!**

Add like terms.

4x + (8 - 20)

Simplify.

4x + (-12)

Get rid of parenthesis.

4x - 12

Look at our answer choices.

Our answer is a. 4x - 12

~Hope I helped!~
3 0
3 years ago
Please helpppp I need a answer asap
FinnZ [79.3K]

Answer:

280cm^2

Step-by-step explanation:

I am only looking for the shaded region which is 20 and 14 and 20*14=280

so my final answer will be 280cm^2

4 0
3 years ago
Helppppp meeee pleaseeee in horrible at math
rosijanka [135]
Circumference = 2×3.14×r
3.14 is pie and r is the radius.
To find the radius you divide the diameter by 2.
19 ÷ 2 = 9.5
2×3.14×9.5 = 59.66
Multiply 59.66 by 6 because ther are 6 pennies.

59.66 × 6 = 357.96 mm.
4 0
3 years ago
Help me asap! I will give you marks
Law Incorporation [45]

Recall the binomial theorem.

(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k

1. The binomial expansion of \left(1+\frac x3\right)^7 is

\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}

Observe that

k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x

k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2

When we multiply these by 8-9x,

• 8 and \frac73 x^2 combine to make \frac{56}3 x^2

• -9x and \frac73 x combine to make -\frac{63}3 x^2 = -21x^2

and the sum of these terms is

\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}

2. The binomial expansion is

\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k

We get the a^6b^2 term when k=2 :

k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2

6 0
1 year ago
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