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kondor19780726 [428]
4 years ago
7

Make 45/12 a mixed number.

Mathematics
1 answer:
Lynna [10]4 years ago
7 0
It would be 3.75 as the problem
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Write an equation for a line perpendicular to y = – 3x – 2 and passing through the point (-9,-1)
choli [55]
Find the negative reciprocal of the slope of the original line and use the point-slope formula
Y -y1 =m(x -x1 ) to find the line perpendicular to y = 3x -2

8 0
3 years ago
What is the answer to
katovenus [111]

Answer:

y\geq2

Step-by-step explanation:

1. switch sides

2. distribute

3. simply (combine like terms) in this case it would go to 22y

4. add 48 to both sides

5. simplify

6. divide

y\geq2

6 0
4 years ago
To join the gym there is a $100 annual fee and a $7 monthly fee for each class you attend.What is the total cost to be a member
marusya05 [52]

Answer:

$184, assuming attendance of one course (not class).

Step-by-step explanation:

Total cost for one year (x) = $100 + ($7/ month)x, where x is the number of months.  

As there are 12 months in one year:

Total cost (12) = $100 + ($7/monthly)(12) = $184

5 0
4 years ago
If p is a polynomial show that lim x→ap(x)=p(a
Lostsunrise [7]

Let p(x) be a polynomial, and suppose that a is any real number. Prove that

lim x→a p(x) = p(a) .

 

Solution. Notice that

 

2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .

 

So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x – 2.

 

Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| < 1, so −2 < x < 0. In particular |x| < 2. So

 

|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|

= 2|x|^3 + 5|x|^2 + |x| + 2

< 2(2)^3 + 5(2)^2 + (2) + 2

= 40

 

Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2 + x − 2| < ε/40 · 40 = ε.

3 0
3 years ago
consider the distance equation d=rt, where d is the distance (in feet), r is the rate (in feet per second), and t is the time (i
vesna_86 [32]

Answer:

  yes, they are proportional

Step-by-step explanation:

A proportion is a relation that can be modeled by a straight line through the  origin. The equation will have the form ...

  y = kx

where x is the independent variable, y is the dependent variable, and k is a constant of proportionality.

__

If you start with the equation relating distance, rate, and time:

  d = rt

and you fix the time at 50 seconds, then the equation becomes ...

  d = 50t

This is the equation of a proportion with a constant of proportionality of 50. It tells you the distance run is proportional to the rate you run. When this equation is graphed, it is a straight line through the origin.

8 0
2 years ago
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