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Art [367]
3 years ago
6

Help me please and thank you !

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
6 0
The answer is <em>B, f(x) = -4x
</em>
<em />This is because all of the outcomes are the x values times -4. <em>
</em>
You might be interested in
Use the standard deviation values of the two samples to find the standard deviation of the sample mean differences.
larisa86 [58]

The standard deviation of the sample mean differences is 4.854

<h3>How to determine the standard deviation of the sample mean differences?</h3>

The table of values is given as:

<u>Sample      Standard deviation</u>

Red box     3.868

Blue box   2.933

The standard deviation of the sample mean differences is calculated using:

\sigma = \sqrt{\sigma_1^2 + \sigma_2^2}

This gives

\sigma = \sqrt{3.868^2 + 2.933^2}

Evaluate the expression

\sigma = 4.854

Also, the table of value do not give any information regarding the sample size.

This means that the sample size of the session regarding the number of people would purchase the red box and the blue box are unknown

Hence, the standard deviation of the sample mean differences is 4.854

Read more about standard deviation at:

brainly.com/question/15858152

#SPJ1

8 0
2 years ago
Can someone help me out :P
ladessa [460]

Answer:

c

Step-by-step explanation:

i think it is c bec 1ft is 6m

6 0
2 years ago
How can i solve this equation to find x?
34kurt

Answer:

x = 25

Step-by-step explanation:

We know that A and M are on a line, which is 180 degrees, and the little square means 90 degrees. So, ∠RAM = 180 - 90 = 90 degrees.

∠RAM = ∠RAX + ∠XAM

90 = (2x - 10) + (-3x + 125)

Now, simply combine like terms and solve for x:

90 = 2x - 3x - 10 + 125

90 = -x + 115

x = 115 - 90 = 25

Thus, x = 25.

<em>~ an aesthetics lover</em>

5 0
3 years ago
Read 2 more answers
5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0
3 years ago
Please help me with my delta math
astra-53 [7]

Answer:

Use “ Math- way”

Step-by-step explanation:

It’s a web browser made for this stuff, you‘re welcome

5 0
3 years ago
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