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Nadya [2.5K]
3 years ago
9

How would you solve 3x+6x+20=92

Mathematics
1 answer:
Radda [10]3 years ago
4 0
3x + 6x + 20 = 92
9x + 20 = 92
9x = 72
x = 8
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What are the first five terms, a1, a2, a3, a4, a5 of the sequence defined by an= n^2-9/ n^3 and how can the sequence be describe
Valentin [98]

The first five terms of the sequence are -8, -5/8, 0, 5/64 and 16/125

<h3>Recursive form of a sequence</h3>

Given the nth term of a sequence expressed as:

an= n^2-9/ n^3

Determine the first five terms

If n = 1

a1 = 1^2-9/ 1^3

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If n = 2

a2 = 2^2-9/ 2^3

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If n = 3

a3= 3^2-9/ 1^3

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If n = 5

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Learn more on recursive function here: brainly.com/question/489759

#SPJ1

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