3 years ago

Is this correct please check I have school in 5 minutes.

2 answers:

8 0

Yes, you got the right answer. As you got it right, I'm not going to explain it, sorry to whomever else needs the explanation :)

emmainna [20.7K]3 years ago

5 0

Yep that looks good,

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In the figure, PQ is parallel to RS. The length of RP is 2 cm; the length of PT is 18 cm; the length of QT is 27 cm. What is the

Sidana [21]

Step 1

Find the value of TS

we know that

if PQ is parallel to RS. then triangles TRS and TPQ are similar

$\frac{TR}{TP} =\frac{TS}{QT}$

solve for TS

$TS =\frac{TR*QT}{TP}$

we have

$RP=2\ cm\\TP=18\ cm\\QT=27\ cm$

$TR=TP+RP\\TR=18+2=20\ cm$

substitute

$TS =\frac{20*27}{18}$

$TS =30\ cm$

Step 2

Find the value of SQ

we know that

$SQ=TS-QT$

we have

$TS =30\ cm$

$QT=27\ cm$

substitute

$SQ=30\ cm-27\ cm=3\ cm$

therefore

the answer is

the value of SQ is $3\ cm$

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What has she done wrong?

Strike441 [17]

Answer:

see explanation

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Her error is in squaring (2y)²

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= 6.25%

= 0.0625

= 625/10000

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