Descriptive language is vivid and specific, and helps someone imagine a scene he didn't witness. ... The word descriptive comes from the Latin descript-, meaning "written down." Something that is descriptive uses an account of words to give us a sense of what it's like.
Answer:
6.125
Step-by-step explanation
1 3/4 times 3 1/2 = 6.125
Your answer is D for your purposes
Work:
Multiply b and 5
Multiply b and 1
The b just gets copied along.
5*b evaluates to 5b
Multiply b and 6
Multiply b and 1
6*b evaluates to 6b
6*b-10 evaluates to 6b-10
Multiply 5b by 6b-10
Multiply 5b by each term in 6b-10 term by term.
This is the distributive property of multiplication.
Multiply 5b and 6b
Multiply the b and b
Multiply b and b
Combine the b and b by adding the exponents, and keeping the b, to get b²
5b × 6b =
Multiply 5b and -10
Multiply b and 1
5b × -10 = -50b
5*b*(6*b-10)
***The final answer is 30b²-50b***
Given problem;
Write and algebraic expression for the number of awards Tomi's band has won;
Let the number of award Tomi's band has won = T
Let the number of award All's band has won = A
We know;
Tomi's band has won twice as many awards as All's band.
T = 2 x A
T = 2A
The algebraic expression is T = 2A
Answer:
10 hours at job (1)
2 hours at job (2)
Step-by-step explanation:
As per the given information, one earns ($8) dollars at one of their jobs, and ($10) hours at the other. One must earn a total of ($100) dollars, and can work no more than (12) hours. Let (x) be the hours worked at job 1 and (y) be the hours worked at job two.
Since one can work no more than (12) hours, the sum of (x) and (y) must be (12), therefore the following equation can be formed;
One earns ($8) dollars at one of their jobs and ($10) at the other, but one earns a total of (100) one can form an equation to represent this situation. Multiply the hours worked by the money earn per hour for each job, add up the result and set it equal to (100).
Now set up these equations in a system;
Use the process of elimination to solve this system. The process of elimination is a method of solving a system of equations. One must first manipulate one of the equations in the system such that one of the variable coefficients is the additive inverse of the other. That way, when one adds the equation, the variable cancels, one can solve for the other variable then back solve to find the value of the first variable,
Manipulate,
Simplify,
Add,
Inverse operations,
Backsolve for (x), use equation one to achieve this,
Substitute,
Inverse operations,