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SOVA2 [1]
3 years ago
7

The formula for calculating simple interest is I = prt. Which is the equivalent equation solved for r? StartFraction I Over p t

EndFraction = r StartFraction p t Over I EndFraction = r I minus p t = r I + p t = r
Mathematics
2 answers:
elena-s [515]3 years ago
7 0

Answer:

Answer: r = I/pt

Step-by-step explanation:

xxTIMURxx [149]3 years ago
3 0

Answer: r = I/pt

Step-by-step explanation:

Interest divided by the principal × time gives the rate. It's usually expressed as a percentage per year.

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-1/2 +2=-x+7 how do you figure this out​
Feliz [49]

Answer:

x = 5.5

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

-\frac{1}{2} +2=-x+7

-\frac{1}{2} +2= 1.5

1.5=-x+7

       -7    -7

-5.5 = -x

Divide both sides by -1.

5.5 = x

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Use the following identity:

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The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among
jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(c) The value of P(at most one) is 0.253.

(d) The event is not unusual.

Step-by-step explanation:

Let <em>X</em> = number of households watching the show.

The probability of the random variable <em>x</em> is, P (X) = <em>p</em> = 0.18.

The sample selected for the survey is of size, <em>n</em> = 14

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 14 and <em>p</em> = 0.18.

The probability of a Binomial distribution is computed using the formula:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-0.062\\=0.938

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

             ={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

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Step-by-step explanation:

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