Answer:
133/143
Step-by-step explanation:
Let S be the sample space
Let E be the event of selecting three committee partners with at least one junior partner.
Partners in the law firm include:
Senior partners = 6
Junior partners = 7
Total partners = 13
n(S) = number of ways of selecting 3 partners from 13 = 13C3
n(S) = 13C3 = 13!/(10!3!) = (13x12x11)/(3x2x1) = 286
To get n(E) i.e least 1 junior partner in the selected committee, we may have:
(2 senior and 1 junior) or ( 1 senior and 2 junior) or (3 junior).
Therefore, the required number of way is given below:
= (6C2 x 7C1) + (6C1 x 7C2) + 7C3
= [(6x5)/2 x 7] + [6 x (7x6)/2] + [(7x6x5)/(3x2)]
= 105 + 126 + 35
n(E) = 266
Therefore, the probability P(E) that at least one of the junior partners is on the committee is given below:
P(E) = n(E) /n(S)
P(E) = 266/286
P(E) = 133/143
Answer:
1.9 is greater than 1.39 if that's what your asking?
Answer:
5 and 3/5ths is the answer to your question
We start by calculating the assessed value, that is 41% of the price.
The price is $92,000.
Then, the assessed value is:
The property tax rate is $39.50 per $1000 of assessed value, so we can express this rate as:
We then can multiply this rate by the assessed value to calculate the total property tax:
NOTE: we could have also multiplied 39.50 by 37.72. The value 37.72 is the thousands of dollars of assessed value. We would have obtained the same result: 39.50*37.72=1489.94.
Answer: the property tax is $1,489.94.
