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Margarita [4]
2 years ago
8

Find the area and circumference of a circle which is 5cm​

Mathematics
2 answers:
Alekssandra [29.7K]2 years ago
7 0

Answer:

Area= 78.5 cm² (3 s.f.)

Circumference= 31.4 cm (3 s.f.)

Step-by-step explanation:

\boxed{area \: of \: circle = \pi {r}^{2} }

In this question, the radius is 5cm thus r= 5.

Area of circle

= π(5²)

= 25π

= 78.5 cm² (3 s.f.)

\boxed{circumference \: of \: circle = 2\pi r}

Circumference of the circle

= 2(π)(5)

= 10π

= 31.4 cm (3 s.f.)

Nonamiya [84]2 years ago
6 0

Answer: 31.416

Step-by-step explanation:

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Melinda spends $5 at each of the 14<br> stores she visits. How much money did she spend ?
Paha777 [63]

Answer:

$70

Step-by-step explanation:

5 dollars * 14 stores= $70

4 0
3 years ago
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The value of the digit 6 in 23,640 is ? Times ? Than the value of the 6 in 167892
lianna [129]

Answer:

The value of the digit 6 in 23,640 is ? Times ? Than the value of the 6 in 167892

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3 years ago
What is the equation of the line that is perpendicular to the given line and passes through the point (3, 4)?
Lady_Fox [76]

Answer:

<h2>y = 3x - 5</h2>

Step-by-step explanation:

\text{The slope-intercept form of an equation of a line:}\\y=mx+b\\m-slope\\b-y\ intercept

\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

\text{Let}\ k:y=m_1x+b_1,\ l:y=m_2x+b_2,\ \text{then}\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\=========================

\text{From the graph we have two points (-3, 2) and (0, 1).}\\\text{Calculate the slope of the given line:}\\\\m=\dfrac{1-2}{0-(-3)}=\dfrac{-1}{3}=-\dfrac{1}{3}.\\\\\text{Therefore the slope of the perpendicular line is:}\\\\m=-\dfrac{1}{-\frac{1}{3}}=3\\\\\text{Put it and the coordinates of the point (3, 4) to the equation of a line:}\\\\4=3(3)+b\\4=9+b\qquad\text{subtract 9 from both sides}\\-5=b\to b=-5\\\\\text{Finally:}\\\\y=3x-5

5 0
3 years ago
What is the product of 2/5 and 2/3​
stich3 [128]

Answer:

4/15 or in decimal form its 0.26

Step-by-step explanation:

4 0
3 years ago
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Abigail and Spencer calculate the slope of the line between the points (3,-1) and (5,4) in different ways. Abigail calculates th
telo118 [61]

Answer:

Spencer and Abigail are correct

Lauren is incorrect

Step-by-step explanation:

Spencer and Abigail are correct

Slope = change in y ÷ change in x

Or  m=\dfrac{y_2-y_1}{x_2-x_1}

Let (x_1,y_1) = (3, -1)

Let (x_2,y_2) = (5, 4)

\implies m=\dfrac{4-(-1)}{5-3}=\dfrac52

This is Spencer's method

Let (x_1,y_1) = (5, 4)

Let (x_2,y_2) = (3, -1)

\implies m=\dfrac{-1-4}{3-5}=\dfrac52

This is Abigail's method

It doesn't matter which point you label as point 1 and point 2, as long as you carry out the slope calculation correctly.

Lauren's calculation is wrong as she calculated her slope as:

m=\dfrac{y_2-y_1}{x_1-x_2}

where it should have been m=\dfrac{y_2-y_1}{x_2-x_1}

4 0
2 years ago
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