Answer:
x are -5/2 and 0 . Y are 0 and 2.
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1 answer:
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The answer is the option d, which is: d)
The explanation for this problem is shown below:
1. Smplify the denominator and rewrite the numerator in this form:
2. Multiply the denominator and the numerator by the conjugated and simplify the expression, as following:
3. As you can see, you obtain the expression shown in the option mentioned above.
To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,
Therefore, 500 gallons of 80% antifreeze solution is required.