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Alexus [3.1K]
3 years ago
14

Find the value of x. Round to the nearest degree. 60 33 57 29

Mathematics
2 answers:
stepan [7]3 years ago
6 0

Answer:

33

Step-by-step explanation:

that is pretty close to a 45 degree angle so i would say about 33

myrzilka [38]3 years ago
3 0

Answer:

33

Step-by-step explanation:

First find the missing side...

11^2 + a^2 = 20^2

121 + a^2 = 400

400 - 121 = a^2

a^2 = 279

a = 16.7

A = 16.7, B = 11, C = 20

20 - 16.7 = 3.3

Estimate

3 x 11 = 33

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On Saturday, Craig rode his bike 5/8 of a mile. On Sunday, he rode his bike 1/2 of a mile. Craig added 5/8 + 1/2 to find the tot
saul85 [17]
Hi there!

Craig's reason is not reasonable because when you add fractions you have to find equivalent fractions.

The total distance in miles would be 1 1/8 miles.

By using a number line, line up the fractions, so then you could add them both.

Hope this helps :)
8 0
3 years ago
Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturd
mestny [16]

Answer:

1) P(X = 8) = 0.1033

P(X = 9) = 0.0688

2) Expected number of 200 restaurants in which exactly 8 customers use the drive-through: 20.66

Expected number of 200 restaurants in which exactly 9 customers use the drive-through: 13.76

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

Question 1. Use the Poisson distribution to calculate the probability that exactly 8 cars will use the drive-through between 12:00 midnight and 12:30 AM on a Saturday night at Wendy's. Do the same for exactly 9 cars.

Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturday nights. This means that during 30 minutes, 6 cars expected to arrive. So \mu = 6.

P(X = 8)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 8) = \frac{e^{-6}*(6)^{8}}{(8)!} = 0.1033

P(X = 9)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 9) = \frac{e^{-6}*(6)^{9}}{(9)!} = 0.0688

Question 2. At how many of the 200 restaurants in the survey would you expect exactly 8 customers to use the drive-through? exactly 9 customers?

There is a 10.33 probability that 8 customers would use the drive through for each restaurant.

So of 200, the expected number is

E(X) = 200*0.1033 = 20.66

There is a 6.88 probability that 9 customers would use the drive through for each restaurant.

So of 200, the expected number is

E(X) = 200*0.0688 = 13.76

8 0
3 years ago
Lines and intersect at O. What is the measure of What do you Understand?<br> What is your Plan/Strategy?<br> Solve and Check you
kakasveta [241]
Uhhhh thank you lol bye?!. huhhhhhuif tgctzc bthfmh. ucync
3 0
2 years ago
.
Vika [28.1K]

Answer:

the answer would be 4/10 but the simplified version would be 2/5.

Step-by-step explanation:

add up how many bows you have, that will be the denominator. Then, the numerator is the number of purple bows. and if your going to simplify it divide the numerator and denominator by 2.

5 0
3 years ago
Read 2 more answers
Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.
Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{1599\text{ years}}

k=4.33\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 1000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=5.19g

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 10000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=0.105g

Thus, the amount after 10000 years will be, 0.105 grams.

4 0
3 years ago
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