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leva [86]
3 years ago
13

If the angle of elevation to a pole is 67 degrees and the wire is attached to the ground at a point 137 feet from the base of th

e pole, what is the HEIGHT of the pole? (round two decimal places)
a. 53.53 feet
b. 74.62 feet
c. 126.11 feet
d. 322.75 feet
Mathematics
1 answer:
Dmitrij [34]3 years ago
6 0
Tan67=h/137

h=137tan67

h≈322.751 ft

h≈322.75 ft  (to nearest hundredth of a foot)
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An item is priced at $13.94. If the sales tax is 4%, what does the item cost including sales tax?
oksano4ka [1.4K]

Answer:

$13.98

Step-by-step explanation:

Convert 4% into decimal = 0.04

Now...

13.94 + 0.04 = 13.98

6 0
3 years ago
I need help in mathematics
lapo4ka [179]

Answer:

B. 75.36 cubic cm

Step-by-step explanation:

We will use the formula V=π times r² times h

so, V= 3.14 times 2² times 6

so, V= 3.14 times 4 times 6

= 3.14 times 24

=75.36 cubic cm

<h2><em>Please mark me as brainliest</em></h2>
6 0
3 years ago
Al factorizar el trinomio cuadrado perfecto, obtenemos el siguiente resultado: (que no se como resolver) xd algun pro que sepa r
PolarNik [594]

Answer:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2

Step-by-step explanation:

<u>Trinomio Cuadrado Perfecto</u>

El producto notable llamado cuadrado de un binomio se expresa como:

(a-b)^2=a^2-2ab+b^2

Si se tiene un trinomio, es posible convertirlo en un cuadrado perfecto si cumple con las condiciones impuestas en la fórmula:

* El primer término es un cuadrado perfecto

* El último término es un cuadrado perfecto

* El segundo término es el doble del proudcto de los dos términos del binomio.

Tenemos la expresión:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

\displaystyle a=\sqrt{\frac{100}{81}m^8p^{12}q^{16}z^2}

\displaystyle a=\frac{10}{9}m^4p^{6}q^{8}z

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

\displaystyle b=\sqrt{\frac{1}{49}m^2p^2z^8

\displaystyle b=\frac{1}{7}mpz^4

Nos cercioramos de que el término central es 2ab:

\displaystyle 2ab=2\frac{10}{9}m^4p^{6}q^{8}z\frac{1}{7}mpz^4

Operando:

\displaystyle 2ab=\frac{20}{63}m^5p^7q^8z^5

Una vez verificado, ahora podemos decir que:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2

5 0
2 years ago
I need answers asap... please
aleksandrvk [35]

Answer:

see explanation

Step-by-step explanation:

(4)

consider the left side

factor the numerator

cosx - cos³x = cosx(1 - cos²x)

\frac{cosx(1-cos^2x)}{sinx}[/tex = [tex]\frac{cosxsin^2x}{sinx}

cancel sinx on numerator/denominator

= cosxsinx =right side ⇒ verified

(5)

Consider the left side

expand the factors

(1 + cotΘ)² + (1 - cotΘ)²

= 1 + 2cotΘ + cot²Θ + 1 - 2cotΘ + cot²Θ

= 2 + 2cot²Θ

= 2(1 + cot²Θ) ← 1 + cot²Θ = cosec²Θ

= 2cosec²Θ = right side ⇒ verified

(6)

Consider the left side

the denominator simplifies to

cosxtanx = cosx × \frac{sinx}{cosx} = sinx

\frac{sin^2x(secx+cosecx)}{sinx}

= sinx( \frac{1}{cosx} + \frac{1}{sinx})

= \frac{sinx}{cosx} + \frac{sinx}{sinx}

= tanx + 1 = right side ⇒ verified











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3 years ago
Question 7 of 10
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3 years ago
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