If you're saying that the scale is 10 cm: 1 mm then the scale will be larger than the actual object because for every 1 mm of the object it will equal 10 cm of the scale drawing.
Answer:
Work individually or in teams of two to construct and launch paper rockets using a teacher-built PVC-pipe launcher.
Following the flight of their rocket, calculate the altitude their rocket achieved.
Based on the flight performance of their rockets, analyze their rocket designs, modify or rebuild them, launch again, and calculate the altitude achieved to determine if their changes affected the performance of the rocket.
Conclude the activity by writing a post-flight mission report.
Materials
Answer: See attached table
Step-by-step explanation:
+---+---+---+
| 1 | 8 | 2 |
+---+---+---+
| 6 | 4 | 2 |
+---+---+---+
| 5 | 0 | 7 |
+---+---+---+
<u>Proofs:</u>
First row: 1+6+5 = 12
Second row: 8+4+0 = 12
Third row: 2+2+7 = 12
First column: 1+8+2 = 12
Second column: 6+4+2 = 12
Third column: 5+0+7 = 12
Diagonal starting from top left to bottom right: 1+4+7 = 12
Diagonal staring from top right to bottom left: 2+4+5 = 12
Answer:
A) y² - 5y + 1
B) y² - 5y - 4
C) - 5y + 1
D) - 3y² - 4y - 6
Step-by-step explanation:
Let's call P the unkown polynomial and D the difference. In each case, the following must be true:
y² - 5y + 1 - P = D
<em>A)</em>
y² - 5y + 1 - P = 0
y² - 5y + 1 = P
<em>B)</em>
y² - 5y + 1 - P = 5
y² - 5y + 1 - 5 = P
y² - 5y - 4 = P
<em>C)</em>
y² - 5y + 1 - P = y²
y² - 5y + 1 - y² = P
- 5y + 1 = P
<em>D) </em>
y² - 5y + 1 - P = 4y² - y + 7
y² - 5y + 1 - 4y² + y - 7 = P
- 3y² - 4y - 6 = P
To find x just set this = to 180 bc is a supp angle so 58+x=180 and then subtract 58 from both sides 180-58=122 rewrite x=122
Hope this helps have a nice day!