Answer:
even
Step-by-step explanation:
because if you put it into mx+b=c you get it as a even answer
Answer: ![JK=8](https://tex.z-dn.net/?f=JK%3D8)
Step-by-step explanation:
You can observe in the figure that JK is a tangent and KH is a secant and both intersect at the point K. Then, according to the Intersecting secant-tangent Theorem:
![JK^2=KE*KH](https://tex.z-dn.net/?f=JK%5E2%3DKE%2AKH)
You know that:
![KH=KE+HE](https://tex.z-dn.net/?f=KH%3DKE%2BHE)
Then KE is:
![KE=KH-HE](https://tex.z-dn.net/?f=KE%3DKH-HE)
![KE=16-12](https://tex.z-dn.net/?f=KE%3D16-12)
![KE=4](https://tex.z-dn.net/?f=KE%3D4)
Now you can substitute the value of KE and the value of KH into
and solve for JK. Then the result is:
D So yea or A I think at least try D
-2x-4
slope always goes first and behind that goes x...
Y = -2x - 5.....slope here is -2. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we will need is : 1/2. See how I flipped the slope of -2/1 and changed it to -1/2.....now I change the sign making our new slope be 1/2.
y = mx + b
slope(m) = 1/2
(-1,-2).....x = -1 and y = -2
now sub and find b, the y int
-2 = 1/2(-1) + b
-2 = -1/2 + b
-2 + 1/2 = b
-4/2 + 1/2 = b
-3/2 = b
so ur perpendicular line is : y = 1/2x - 3/2