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IRINA_888 [86]
2 years ago
14

PLEASE HELP ME I WILL MARK BRAINLIEST!!!

Mathematics
1 answer:
alexandr402 [8]2 years ago
7 0

1. One way to approach this is to convert the magnitude and direction of each force to rectangular coordinates.

... first force = 90(cos(30°), sin(30°)) = (77.94, 45.00)

... second force = 50(cos(160°), sin(160°)) = (-46.98, 17.10)

Then their sum is

... resultant force = first force + second force = (30.96, 62.10)

The magnitude is found using the Pythagorean theorem:

... resultant magnitude = √(30.96^2 + 62.10^2)

... ... = √(958.52+3856.41) = √4814.93

... ... = 69.39

The resultant direction can be found using the definition of the tangent function.

... tan(α) = 62.10/30.96 = 2.01

... α = arctan(2.01) = 63.55°

The (magnitude, direction) of the resultant force are (69.39, 63.55°).

_____

(Note that rounding introduced an error of 0.05° in the direction.)

2. Using DeMoivre's theorem, the magnitude of the 4th root is the 4th root of the magnitude, and the angle of the 4th root is 1/4 of the angle (and its aliases).

... fourth root = 256^(1/4)∠((240°+k*360°)/4) = 4∠(60°+k*90°) . . . . k=0, 1, 2, 3

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Which function is increasing?? :)
exis [7]

Answer:

\large\boxed{B.\ f(x)=4^x}

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A.\ f(x)=\left(\dfrac{1}{4}\right)^x\to a=\dfrac{1}{4}\in(0,\ 1)\to\text{decreasing}\\\\B.\ f(x)=4^x\to a=4\in(1,\ \infty)\to\text{increasing}\\\\C.\ f(x)=(0.4)^x\to a=0.4\in(0,\ 1)\to\text{decreasing}\\\\D.\ f(x)=\left(\dfrac{1}{2}\right)^x\to a=\dfrac{1}{2}\in(0,\ 1)\to\text{decreasing}

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3 years ago
. Using the Binomial Theorem explicitly, give the 15th term in the expansion of (-2x + 1)^19
timofeeve [1]
Let's rewrite the binomial as:
(1 - 2x)^{19}

\text{Binomial expansion:} (1 + x)^{n} = \sum_{r = 0}^n\left(\begin{array}{ccc}n\\r\end{array}\right) (x)^{r}

Using the binomial expansion, we get:
\text{Binomial expansion: } (1 - 2x)^{19} = \sum_{r = 0}^{19}\left(\begin{array}{ccc}19\\r\end{array}\right) (-2x)^{r}

For the 15th term, we want the term where r is equal to 14, because of the fact that the first term starts when r = 0. Thus, for the 15th term, we need to include the 0th or the first term of the binomial expansion.

Thus, the fifteenth term is:
\text{Binomial expansion (15th term):} \left(\begin{array}{ccc}19\\14\end{array}\right) (-2x)^{14}
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3 years ago
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