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3 years ago

Solve for x. * 52° (6x + 2)°

Mathematics

2 answers:

DiKsa [7]3 years ago

5 0

Answer:

Step-by-step explanation:

pickupchik [31]3 years ago

4 0

Answer:

x=21

Step-by-step explanation:

The two angles form a straight line so they add to 180

6x+2+52 = 180

6x+54= 180

Subtract 54 from each side

6x+54-54 = 180-54

6x= 126

Divide by 6

6x/6 =126/6

x = 21

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Dominik [7]

Answer:

Step-by-step explanation:

4 0

2 years ago

The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2 : 3, what is the rati

Ksivusya [100]

<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

$\dfrac{24}{25}$

<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

$Perimeter\ of\ R=2(2x+3x)$

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

$Perimeter=2(L+B)$ )

Hence, we get:

$Perimeter\ of\ R=2(5x)$

i.e.

$Perimeter\ of\ R=10x$

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

$\text{Perimeter\ of\ square}=4s$

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

$4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}$

Now, we know that the area of a square is given by:

$\text{Area\ of\ square}=s^2$

and

$\text{Area\ of\ Rectangle}=L\times B$

Hence, we get:

$\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}$

and

$\text{Area\ of\ Rectangle}=2x\times 3x$

i.e.

$\text{Area\ of\ Rectangle}=6x^2$

Hence,

Ratio of the area of region R to the area of region S is:

$=\dfrac{6x^2}{\dfrac{25x^2}{4}}\\\\=\dfrac{6x^2\times 4}{25x^2}\\\\=\dfrac{24}{25}$

6 0

3 years ago

Read 2 more answers

A ball is dropped from a certain height. The function below represents the height f(n), in feet, to which the ball bounces at th

natali 33 [55]

Answer:

9 represents the initial height from which the ball was dropped

Step-by-step explanation:

Bouncing of a ball can be expressed by a Geometric Progression. The function for the given scenario is:

$f(n)=9(0.7)^{n}$

The general formula for the geometric progression modelling this scenario is:

$f(n)=f_{0}(r)^{n}$

Here,

$f_{0}$ represents the initial height i.e. the height from which the object was dropped.

r represents the percentage the object covers with respect to the previous bounce.

Comparing the given scenario with general equation, we can write:

$f_{0}$ = 9

r = 0.7 = 70%

i.e. the ball was dropped from the height of 9 feet initially and it bounces back to 70% of its previous height every time.

7 0

2 years ago

Does 2^8 equal (3sqrt{16})^6

ale4655 [162]

Answer:

Does 2⁸ = (3√16)⁶? No.

Step-by-step explanation:

2⁸ = (3√16)⁶

Evaluate 2⁸. This can simply be written out as:

2 * 2 * 2 * 2 * 2 * 2 * 2 * 2

4 * 2 * 2 * 2 * 2 * 2 * 2

8 * 2 * 2 * 2 * 2 * 2

16 * 2 * 2 * 2 * 2

32 * 2 * 2 * 2

64 * 2 * 2

128 * 2

256.

256 = (3√16)⁶

Evaluate √16.

256 = (3*4)⁶

Multiply 3 and 4.

256 = 12⁶

Evaluate 12⁶. This can be rewritten as:

12 * 12 * 12 * 12 * 12 * 12

144 * 12 * 12 * 12 * 12

1728 * 12 * 12 * 12

20736 * 12 * 12

248832 * 12

2985984.

Since 256 ≠ 2985984, the answer to this question is no.

4 0

2 years ago

3y - 5x = 9<br> Y= -5/3x-12<br> Are the parallel

bija089 [108]

Answer:

Both lines are not parallel

Step-by-step explanation:

Given as :

Two lines equation are as :

3y - 5x = 9 And y = - $\frac{5}{3}$ x - 12

First line is now written in eq y = mx + c

Or, 3y = 5x + 9

Or, y = $\frac{5}{3}$ x + $\frac{9}{3}$

So, Slop of this line ( m 1 ) = $\frac{5}{3}$

slop of second line ( m 2) is $\frac{- 5}{3}$

∵ The slop of both lines are not equal , so the line are not parallel to each other .

Hence Both lines are not parallel Answer

6 0

3 years ago