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Aleks04 [339]
3 years ago
9

Help please i need it quickly

Mathematics
2 answers:
Minchanka [31]3 years ago
8 0
The answer is 2 ......
VLD [36.1K]3 years ago
5 0
8x0.25=2. the answer is 2
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The power 9 squared is equivalent to 81. What is the value of 9 Superscript negative 2? Negative 81 Negative 9 StartFraction 1 O
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1/81

Step-by-step explanation:

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Add the two expressions. −4.2x+3 and 2.5x−6 Enter your answer in the box.
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= - 4.2x + 3 + 2.5x - 6

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During a basketball practice, Steph Curry made 234 three point shots in 45 minutes,
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2 years ago
A popular magazine tests cars and trucks for mileage on the road and around the city. The magazine reports that the most common
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It shows that the values of the mileages are close to 24 mpg. Hence statistics refes 24 as the mean.

<h3>Mean of a data.</h3>

Mean is one of the measure of dispersion and is the avearage of a set of data.

According to the question, the magazine reports that the most common gas mileage was 24 mpg. This shows that reports have published several gas mileages for cars and truck and the average of this mileage is 24mpg

It shows that the values of the mileages are close to 24 mpg. Hence statistics refes 24 as the mean.

Learn more on mean here: brainly.com/question/14532771

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2 years ago
An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

5 0
3 years ago
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