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4 years ago

List and describe at least six things that differentiate living and non-living things.?

Biology

1 answer:

jonny [76]4 years ago

6 0

Difference Between Living & Non-Living Things.

Answer:

To List Is:

i) Excretion

ii) Sensitivity

iii) Growth

iv) Reproduction

v) Respiration

vi) Nutrition

Explanation: Description:

(a) Excretion: Is the process by which living things remove metabolic waste substances from the body.

Living things excrete whiles non-living things do not excrete.

(b) Sensitivity: Is theprocess by which living things responds to stimuli or touch.

Living things responds to stimuli whiles non-living things do not respond to stimuli.

Living things grow whiles non-living things do not grow.

(d) Reproduction: Is the process by which living things produce young ones of their own.

Living things reproduce whiles non-living things do not reproduce.

(e) Respiration: Is the process by which living things breathe or respire [carbon dioxide/oxygen] in order to obtain energy for their activities.

Living things breathe whiles non-living things do not respire.

(f) Nutrition: Is the process by which living things obtain or make food or feed.

Living things feed whiles non-living things do not feed.

<h3>Hope it helps!!</h3><h3>Please mark me as the brainliest!!!</h3>

✨Thanks!!!!✨

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4 years ago

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Explanation:

<h3>I hope this helps!</h3>

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3 years ago

A man has extra digits (six fingers on each hand and six toes on each foot). His wife and their daughter have the normal number

alukav5142 [94]

Options for the question have not been given. They are as follows:

A) 1/8

B) 3/4

C) 1/16

D) 1/2

Answer:

D) 1/2

Explanation:

Let the allele for extra digits be represented by D. Since it is a dominant trait, DD and Dd will result in extra digits whereas dd will result in normal number of digits. The woman has normal number of digits so she has dd genotype. The man has extra digits so he can be either DD or Dd.

The couple's first child has normal number of digits so she has dd genotype. She has obtained one d allele from her mother and another d allele from her father. Hence, the man's genotype is Dd.

Man = Dd

Woman = dd

Their children :

D d

d Dd dd

Half of the progeny will have Dd genotype and will have extra digits. Other half will have dd genotype and will have normal number of digits. So, the probability of their next child to have extra digits is 1/2.

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4 years ago

Who specializes in treatment of diseases of the rectum and anus?

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3 years ago

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Answer:

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Explanation:

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3 years ago