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Butoxors [25]
2 years ago
10

A gym charges 9.00 per hour of childcare. Gym b chargers 0.75 per 5 minutes of childcare. Which comparison of the childcare cost

is accurate
Mathematics
1 answer:
lukranit [14]2 years ago
7 0
Gym a charges = 9.00
Gym b charges = 0.75

We know, Accuracy depends on number of "Significant figures", as gym a charges has only 1 s.f., it is less accurate then gym b charges which has 3 s.f.

In short, Your Answer would be Gym b

Hope this helps!
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2(2h)+2h=p
lesya692 [45]

Answer:

P= 6h

Step-by-step explanation:

2(2h)+2h=p

(2*2h)+ 2h=p

4h+2h=p

6h

6 0
3 years ago
Item 1 Solve the system of linear equations by graphing. 5x+5y=15 2x−2y=10
Marysya12 [62]

After graphing both lines, we're able to tell the solution by looking at the point where the lines cross. In this case, it's at (4, -1). And so that is the solution set.

6 0
3 years ago
8x - 16 = -4x - 4(1-6x)<br> please show work
iris [78.8K]

Answer:

x= -1

Step-by-step explanation:

8x - 16 = -4x - 4(1-6x)

8x - 16 = -4x - 4+24x

8x - 16 = 20x-4

8x - 16+16 = 20x-4+16

8x = 20x+12

8x-20x = 20x-20x+12

-12x=12

Divide both by -12, and you get -1.

3 0
3 years ago
Read 2 more answers
Which pair are equal trig values? A) tan 45° and sin 45° B) sin 40° and sin 50° C) sin 36° and cos 54° D) cos 65° and sin 65°
ipn [44]
The values of the simplified or solved trigonometric functions that are equal are sin and cos, given that the angles are complementary. From the choices above, the answer would be letter C. 
                     sin 36° = 0.5877
                     cos 54° = 0.5877
It can also be observed that 36° and 54° will sum up to 90°. 
4 0
2 years ago
Given that sin(90 -5thetha) = Cos(180 - 0),<br>Find the value of theta​
Dmitry [639]

Answer:

θ = 54 - π/10 - (2 π n_1)/5 for n_1 element Z

or θ = -18 - π/10 - (2 π n_2)/5 for n_2 element Z

Step-by-step explanation:

Solve for θ:

sin(90 - 5 θ) = cos(180)

Hint: | Express the right hand side in terms of sine.

Rewrite the right hand side using cos(θ) = sin(θ + π/2):

sin(90 - 5 θ) = sin(π/2 + 180)

Hint: | Eliminate the sine from the left hand side.

Take the inverse sine of both sides:

90 - 5 θ = -180 + π/2 + 2 π n_1 for n_1 element Z

or 90 - 5 θ = 180 + π/2 + 2 π n_2 for n_2 element Z

Hint: | Look at the first equation: Isolate terms with θ to the left hand side.

Subtract 90 from both sides:

-5 θ = -270 + π/2 + 2 π n_1 for n_1 element Z

or 90 - 5 θ = 180 + π/2 + 2 π n_2 for n_2 element Z

Hint: | Solve for θ.

Divide both sides by -5:

θ = 54 - π/10 - (2 π n_1)/5 for n_1 element Z

or 90 - 5 θ = 180 + π/2 + 2 π n_2 for n_2 element Z

Hint: | Look at the second equation: Isolate terms with θ to the left hand side.

Subtract 90 from both sides:

θ = 54 - π/10 - (2 π n_1)/5 for n_1 element Z

or -5 θ = 90 + π/2 + 2 π n_2 for n_2 element Z

Hint: | Solve for θ.

Divide both sides by -5:

Answer: θ = 54 - π/10 - (2 π n_1)/5 for n_1 element Z

or θ = -18 - π/10 - (2 π n_2)/5 for n_2 element Z

4 0
2 years ago
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