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2 years ago

Which of the following expressions can be used to find the area of a square with a side length of fraction 1 over 3 m?

Mathematics

1 answer:

zlopas [31]2 years ago

4 0

Answer:

The answer is A.

Step-by-step explanation:

Since it is a square we are finding the area of, we are multiplying two numbers. Which means 1/3 by the power of 2.

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Which of the following is located over the center of the base of a regular pyramid

kenny6666 [7]

Vertex is located over the center of the base of a regular pyramid.

<h3>What is Vertex Angle?</h3>

Vertex angle is defined as the angle formed by two lines or rays that intersect at a point. These two rays make the sides of the angle.

Here, Vertex is the point which is located over the center of the base of a regular pyramid.

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brainly.com/question/2028172

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1 year ago

What is the product of 0.6 and 7

Lunna [17]

Product means multiplication.

0.6 * 7 = 4.2

8 0

3 years ago

Read 2 more answers

20% of what number is 30? Pick the proportion that could be used to solve.

Colt1911 [192]

30 is 20% of 150

Working out percentage problems of the form "30 is 20 percent of what number?"

We have, 20% × x = 30

or,

20/100 × x = 30

Multiplying both sides by 100 and dividing both sides by 20,

we have x = 30 × 100/20

x = 150

If you are using a calculator, simply enter 30×100÷20, which will give you the answer.

5 0

2 years ago

A basin has the shape of a prism. What is the capacity of this basin? *

dolphi86 [110]

I think it’s c.....

3 0

2 years ago

Please help!!!!

tatyana61 [14]

Answer:

Step-by-step explanation:

From the figure attached,

If the figures shown are congruent (Equal in shape and size), length of all the sides must be equal.

Therefore, sides sides CD and GH must be equal in measures.

Distance between the two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Length of the side CD having ends C(-4, 4) and D(0, 5) will be,

CD = $\sqrt{(-4-0)^2+(4-5)^2}$

CD = $\sqrt{(16+1)}$

= $\sqrt{17}$

Length of GH having ends G(0, -4) and H(4, -5) will be,

GH = $\sqrt{(0-4)^2+(-4+5)^2}$

= $\sqrt{16+1}$

= $\sqrt{17}$

Therefore, m(CD) = m(GH)

Similarly, we can prove all corresponding sides of two figures equal in measure.

This shows ABCD ≅ EFGH.

3 0

2 years ago