Idk if your a big or girl so here are my guesses...
Henry?????
Puppy?????
Max????
Emily?????
Bethany???
Margaret???
Tiffany??
Arleny???
Answer:
Option(D)
Step-by-step explanation:
Given are the two triangles, that are ABC and DEF, in which AB=8ft, DE=6ft, AC=10ft and DF=7.5ft.
For the two triangles to be similar, it must satisfy the similarity condition that is:
Both the triangles must have congruent angles and the sides should be proportional. Since, two sides of the given triangles are not proportional.Moreover, ∠A=25° and ∠D=24° which are not equal and ∠C=60° and ∠F=61° which are also not equal.
Therefore, Not all the angles are congruent, thus the triangles cannot be similar.
the solid is made up of 2 regular octagons, 8 sides, joined up by 8 rectangles, one on each side towards the other octagonal face.
from the figure, we can see that the apothem is 5 for the octagons, and since each side is 3 cm long, the perimeter of one octagon is 3*8 = 24.
the standing up sides are simply rectangles of 8x3.
if we can just get the area of all those ten figures, and sum them up, that'd be the area of the solid.
![\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=5\\ p=24 \end{cases}\implies A=\cfrac{1}{2}(5)(24)\implies \stackrel{\textit{just for one octagon}}{A=60} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{two octagon's area}}{2(60)}~~+~~\stackrel{\textit{eight rectangle's area}}{8(3\cdot 8)}\implies 120+192\implies 312](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20regular%20polygon%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dap~~%20%5Cbegin%7Bcases%7D%20a%3Dapothem%5C%5C%20p%3Dperimeter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D5%5C%5C%20p%3D24%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%285%29%2824%29%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bjust%20for%20one%20octagon%7D%7D%7BA%3D60%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwo%20octagon%27s%20area%7D%7D%7B2%2860%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Beight%20rectangle%27s%20area%7D%7D%7B8%283%5Ccdot%208%29%7D%5Cimplies%20120%2B192%5Cimplies%20312)
The expression for the cost of the ABC Book Club is 2<em>x </em>+ 40. The expression for the cost of the Easy Book Club is 3<em>x</em> + 35. To find when the total charge for both book clubs is equal, the two expressions must equal each other. (<em>x </em>= the number of books read)
2<em>x </em>+ 40 = 3<em>x</em> + 35
Subtract 35 from both sides.
2<em>x </em>+ 5 = 3x
Subtract 2<em>x </em>from both sides.
5 = <em>x</em>
So, the total charge for each club is equal when 5 books are read.
