Let's factorise it :
Using Distributive property we get :
⠀
Therefore,
A spere has a diameter of 24 units what is the volume in cubic units
1 answer:
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Answer:
El área de la finca que está sembrada por café es 360 m².
Step-by-step explanation:
La finca de Federico tiene tiene un área de 576 m². de la finca están sembrados de naranjas. Entonces, el área de la finca que está sembrada por naranjas se calcula mediante:
576 m²* = 216 m²
Sabiendo que el resto de la finca esta sembrada de café, esta área se calcula mediante la diferencia del área total de la finca y el área sembrada por naranjas:
576 m² - 216 m²= 360 m²
<u><em>El área de la finca que está sembrada por café es 360 m².</em></u>
Answer: option d. x = 3π/2
Solution:
function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
Solution:
function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).