Amylase converts starch to glucose. So the one that didn't have starch in it would not show glucose formation because the amylase didn't have starch to convert to glucose.
Answer:True
Explanation:
The complex molecules are broken down by the digestive system. If the molecules were not to be broken down they would block the system
Answer: A federally funded research study involving children 8 to 12 years old involves collecting a single voided urine sample to assess the frequency of asymptomatic <em>proteinuria</em>.
Your IRB has determined that assent of children age 8 and older is required for the study. A 10 year old firmly declined to participate in the study.
The best procedure that describes the <u>action </u>to be taken by the investigator is:
- Honor the Childs decision .
Explanation:
The <em>purpose</em> of the IRB is to <em>assure that appropriate steps are taken</em> to <em>protect the rights </em>and welfare of humans participating as subjects in a research study. It promotes <em>fully informed and voluntary participation</em> by prospective subjects capable of making such choices (or, if that is not possible, informed permission given by a suitable proxy), and seeks to maximize the safety of subjects.
The capacity admits degrees. The same patient may be able to decide certain things and not others. So, the more transcendent or delicate a decision is, the higher the level of capacity required must be. When the patient <u>is not capable, it is up to his relatives to make the decisions.</u>
A genus of gram-positive, microaerophilic, rod-shaped bacteria occurring widely in nature. Its species are also part of the many normal flora of the mouth, intestinal tract, and vagina of many mammals, including humans. Pathogenicity from this genus is rare.
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Answer:
A. 50% Type A, 50% Type B
Explanation:
To answer this we can draw a punnett square.
Since o if recessive, it can only be expressed if it is not masked by a dominant allele. Therefore the male with type O blood has the genotype oo. A and B are co-dominant, so the woman has genotype AB.
_ | A | B
o |Ao | Bo
o | Ao | Bo
Since A and B are dominant alleles, they will mask the o allele. Therefore genotype Ao will be a Type A phenotype, and genotype Bo will be a Type B phenotype.
Therefore, the phenotypic probabilities for this cross is 50% Type A, 50% Type B. Hence, the answer is A.
Hope this helped!
