What two numbers add up to get -23 and multiply 120

jarptica [38.1K]

<h3>1.Area of the parallelogram= 288 square units</h3><h3>2.Area of the parallelogram=45 $m^2$ </h3><h3>3.Area of the trapezoid = 34 square in.</h3><h3>4.Area of the trapezoid = 8 square ft</h3><h3>5.Area of the rhombus= 27 square cm</h3><h3>6.Area of the rhombus= 108 square in</h3><h3>7.The area of the desktop is = 1200 square in</h3><h3>8.The area of the rhombus is =84 $cm^2$ </h3><h3>9.Area of the trapezoid = 240 square ft</h3>

Step-by-step explanation:

1.

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

=16× 18 square units

= 288 square units

2.

Base = 9 m and height = 5 m

Area of the parallelogram = base × height

=(9×5) $m^2$

=45 $m^2$

3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the trapezoid = $\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

$=\frac{1}{2} \times (12+5) \times 4$ square in.

= 34 square in.

4.

Height = 2 ft and parallel sides are 2 ft and 6 ft

Area of the trapezoid = $\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

$=\frac{1}{2} \times (2+6) \times 2$ square ft

= 8 square ft

5.

Diagonals are 6 cm and 9 cm.

Area of the rhombus $= \frac{1}{2}\times {\textrm{product of diagonals}$

$=\frac{1}{2 } \times 6\times 9$ square cm

= 27 square cm

6. Diagonals are 12 in and 18 in

Area of the rhombus $= \frac{1}{2}\times {\textrm{product of diagonals}$

$=\frac{1}{2 } \times 12\times 18$ square in

= 108 square in

7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in

The area of the desktop is = (30 × 40 ) square in

= 1200 square in

8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.

The area of the rhombus = $\frac {1}{2} \times 14 \times 12$ $cm^2$

=84 $cm^2$

9.Given , the base of trapezoid are 24 ft and 16 ft and height is 12 ft

Area of the trapezoid = $\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

= $\frac{1}{2} \times (24+16) \times 12$ square ft

= 240 square ft

8 0

3 years ago

La catul numerelor 27 si 3 adauga o patrime din 32

Jlenok [28]

27 : 3 = 9
32 :4 =8 (patrimea)
9+8 = 17

7 0

3 years ago

Nike Super Sale $$$ (Additional Instructions in Photo) !!25 POINTS!!

mr Goodwill [35]

The markup percentage regarding the sale of the good will be 136%.

<h3>How to calculate the percentage?</h3>

From the information given, the initial cost is $55.00 and the new price is $130.19. The increase in percentage will be:

= (130.19 - 55)/55 × 100

= 75.19/55 × 100

= 136%

Therefore, the markup percentage regarding the sale of the good will be 136%.

Learn more about percentage on:

brainly.com/question/24304697

#SPJ1

5 0

2 years ago

Tower one, a cube with a hexagonal prism measures 15.6cm. Tower two, a cube with a cylinder measures 18.3cm. Tower 3, a hexagona

lina2011 [118]

Answer:

$Tower 4 = 23.9cm$

Step-by-step explanation:

Given

Tower one = 15.6 cm

Tower two = 18.3 cm

Tower 3 = 13.9 cm.

Required:

Height of the 4th tower

Represent a cube by X; a cylinder by Y and a hexagonal prism by Z

Tower one, a cube with a hexagonal prism = X + Z = 15.6

Tower two, a cube with a cylinder = X + Y = 18.3

Tower 3, a hexagonal prism with a cylinder = Z + Y = 13.9

$X + Z = 15.6$ ----- Equation 1

$X + Y = 18.3$ ----- Equation 2

$Z + Y = 13.9$ ----- Equation 3

Subtract equation 1 from 2

$(X + Y = 18.3) - (X + Z = 15.6)$

$X - X + Y - Z = 18.3 -15.6$

$Y - Z = 18.3 -15.6$

$Y - Z = 2.7$ ---- Equation 4

Add Equation 4 to Equation 3

$(Y - Z = 2.7) + (Z + Y = 13.9)$

$Y + Y - Z + Z = 2.7+ 13.9$

$2Y = 2.7+ 13.9$

$2Y = 16.6$

Divide both sides by 2

$\frac{2Y}{2} = \frac{16.6}{2}$

$Y = \frac{16.6}{2}$

$Y = 8.3cm$

Substitute $Y = 8.3cm$ in Equation 2 and 3

$X + Y = 18.3$ ----- Equation 2

$X + 8.3 = 18.3$

Subtract 8.3 from both sides

$X + 8.3 - 8.3 = 18.3 - 8.3$

$X = 18.3 - 8.3$

$X = 10cm$

$Z + Y = 13.9$ ----- Equation 3

$Z + 8.3 = 13.9$

Subtract 8.3 from both sides

$Z + 8.3 - 8.3 = 13.9 - 8.3$

$Z = 13.9 - 8.3$

$Z = 5.6cm$

So, we have that

$X = 10cm$

$Y = 8.3cm$

$Z = 5.6cm$

The question states that the 4th tower is made up of the three shapes;

This implies that;

$Tower 4 = X + Y + Z$

$Tower 4 = 10cm + 8.3cm + 5.6cm$

$Tower 4 = 23.9cm$

The height of the 4th tower is 23.9cm

8 0

4 years ago

The purpose of this form is so that your employer can withhold the correct amount of federal income tax from your pay.

Jet001 [13]

I-9 form, hope this helps

3 0

3 years ago