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Umnica [9.8K]
3 years ago
9

Which value satisfies the inequality -2x + 8 + 5x > 2x + 1? A) -15 B) -10 C) -7 D) -5

Mathematics
2 answers:
larisa86 [58]3 years ago
8 0

It’s D.) -5

If you solve it you will know x>-7 and the only value that satisfies the equality is -5.

Novosadov [1.4K]3 years ago
5 0
<span>-2x + 8 + 5x > 2x + 1
3x + 8 > 2x + 1
         x > -7

answer
D) - 5</span>
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Jackson purchased a pack of game cards that was on sale for 22% off. The sales tax in his county is 6%. Let y represent the orig
Ymorist [56]

Answer:

Final cost = 0.9328y

Step-by-step explanation:

Assume,

Original price = y

Given:

Discount = 22%

Sales tax = 6%

Computation:

Sales tax will be added on sale value

So,

Sales price = y[100%-22%]

Sales price = 0.88y

Price after sales tax :

Final cost = 0.88y[100% + 6%]

Final cost = 0.88y[106%]

Final cost = 0.9328y

8 0
2 years ago
How to solve 2 3/4 - 1 5/8
daser333 [38]

Answer:

1 1/8

Step-by-step explanation:

First, Make the first fraction into a new one with an equal denominator. (3/4 x2= 6/8)

Then, subtract the whole numbers (2-1=1) and the fractions (6/8-5/8= 1/8)

Lastly, add your two differences together and you get 1 1/8.

6 0
3 years ago
Isabel is running for president of the chess club, and she received 33 votes. There are 60 members in the club. What percentage
iVinArrow [24]

Answer:

55%

Step-by-step explanation:

(Received number of votes/Total number of votes)100%

=(33/60)100%

=(11/20)100%

=(0.55)100%

=55%

Therefore, 55% of the club members voted for Isabel.


4 0
3 years ago
Find the area of the polygon.
zalisa [80]

Answer:

A=128\ cm^2

Step-by-step explanation:

we know that

The area of the polygon is equal to the area of a square plus the area of four congruent triangles

so

A=b^2+4[\frac{1}{2}(b)(h)]

where

b=8\ cm\\h=4\ cm

substitute

A=8^2+4[\frac{1}{2}(8)(4)]

A=64+64=128\ cm^2

4 0
3 years ago
For what value of c will this function have one zero?<br> f(x) = X^2 +c
Phoenix [80]
X² + c is actually a quadratic function.

And x² + c = 0,  it usually has two zeros which are solutions.

But for when c = 0,

x² + c = 0

x² + 0 = 0

x² = 0

Taking the square root of both sides.

x = 0.  Here it only has one zero.

So the function x² + c,  only has one root for  c = 0.
6 0
3 years ago
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