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Lostsunrise [7]
2 years ago
13

The cookie recipe calls for 1/2 cup of flour to make 8 servings. How many cups of flour are needed to make 20 servings of cookie

s? Explain.
Mathematics
2 answers:
Musya8 [376]2 years ago
5 0
20/8=2.5 1/2+1/2+1/2=1 1/2
ivolga24 [154]2 years ago
3 0
Lets see...........8x3=24 8x2=16 1/2x16=16/2= 8 that's not right

ah I really don't know, idk but that stuff at the top should help a little bit. Sorry :(
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April invests in an annually compounded account with an interest rate of 4.1%. After 6 years, she plans to have $8600 in her acc
SOVA2 [1]

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Step-by-step explanation:

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3 0
2 years ago
Which of the following represents the translation of M (8,-2) along vector<-5, 1 > and its reflection
Ulleksa [173]

Step-by-step explanation:

M(8.-2), M'(x,y) , $$\overrightarrow{v} =(-5,1)

$$\overrightarrow{MM'} = $$\overrightarrow{v}

--> x - 8 = -5 --> x= 3

---> y+2 = 1 --> y =-1

so M'(3,-1) and its reflection y-axis is (-3,-1)

4 0
2 years ago
How many pages would same have finished in 126 minutes
Sedaia [141]

Answer:

Sam will finish 42 pages in 126 minutes.

Step-by-step explanation:

Number of pages read by Sam = 6

Time taken to read these pages = 18 minutes

Rate at which Sam is reading the pages of the book = \frac{\text{Number of pages read}}{\text{Time taken to read these pages}}

= \frac{6}{18}

= \frac{1}{3} pages per minute

Number of pages read in 126 minutes = Rate of reading × Time

                                                            = \frac{1}{3}\times 126

                                                            = 42 pages

Therefore, Sam will finish 42 pages in 126 minutes.

3 0
3 years ago
The reading speed of sixth-grade students is approximately normal, with a mean speed of 125 words per minute and a standard devi
Lisa [10]

Answer:

<u>Part A</u>

<u>μ of the reading speed of sixth-grade students = 125 words</u>

<u>σ of the reading speed of sixth-grade students = 24 words</u>

<u>Part B</u>

<u>The probability that a randomly selected sixth-grade student reads less than 100 words per minute is 14.92%</u>

<u>Part C</u>

<u>The probability that a randomly selected sixth-grade student reads more than 140 words per minute is 26.43% </u>

Step-by-step explanation:

Part A:

μ of the reading speed of sixth-grade students = 125 words

σ of the reading speed of sixth-grade students = 24 words

Part B:

1. Let's find the z-score for a randomly selected sixth-grade student that reads less than 100 words per minute:

z-score = (100 - 125)/24

z-score = -25/24

z-score = -1.04

2. Now, let's find out the probability that a randomly selected sixth-grade student that reads less than 100 words per minute, using the z-table:

P (-1.04) = 0.1492

<u>This means that the probability that a randomly selected sixth-grade student that reads less than 100 words per minute is 14.92%</u>

Part C.

1. Let's find the z-score for a randomly selected sixth-grade student that reads more than 140 words per minute:

z-score = (140 - 125)/24

z-score = 15/24

z-score = 0.63

2. Now, let's find out the probability that a randomly selected sixth-grade student that reads more than 140 words per minute, using the z-table:

P (0.63) = 0.7357

But we're being asked for a randomly selected student that reads more than 140 words, then:

1 - P(0.63) = 1 - 0.7357 = 0.2643

<u>This means that the probability that a randomly selected sixth-grade student that reads more than 140 words per minute is 26.43%</u>

8 0
3 years ago
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