A transformation that goes around a fixed point in a circular motion is called a

What is the simplified form of 4x plus 2 over x plus 5 minus the fraction 3x plus 1 over x plus 5?

viva [34]

We have that

[(4x+2)/(x+5)]-[(3x+1)/(x+5)]
They have common denominators, so just add the numerators like normal fractions:
=[(4x+2)-(3x+1)]/(x+5)
=[(4x+2-3x-1)]/(x+5)
=[(x+1)]/(x+5)

the answer is
(x+1)/(x+5)

4 0

3 years ago

Read 2 more answers

Show how you can use repeated subtraction to find 84÷6

Ganezh [65]

84-14-14-14-14-14-14

7 0

4 years ago

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The base is a 45 45 90 triangle with a leg of 5 in. The height is 1.8 what’s the volume of the prism

hjlf

brainly.com/question/3774542 Try this it might help

6 0

4 years ago

Brianna's family spent $134 on 2 adult tickets and 3 youth tickets at an amusement park. Max's family spent $146 on 3 adults tic

Firdavs [7]

The price of 1 youth ticket is $ 22

Solution:

Let "y" be the price of 1 youth ticket

Let "a" be the price of 1 adult ticket

To find: price of 1 youth ticket

Brianna's family spent $134 on 2 adult tickets and 3 youth tickets at an amusement park

So we can frame a equation as:

2 adult tickets x price of 1 adult ticket + 3 youth tickets x price of 1 youth ticket = 134

$2 \times a + 3 \times y = 134$

2a + 3y = 134 ---- eqn 1

Max's family spent $146 on 3 adults tickets and 2 youth tickets

So we can frame a equation as:

3 adult tickets x price of 1 adult ticket + 2 youth tickets x price of 1 youth ticket = 146

$3 \times a + 2 \times y = 146$

3a + 2y = 146 ----- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "y"

Multiply eqn 1 by 3

6a + 9y = 402 ---- eqn 3

Multiply eqn 2 by 2

6a + 4y = 292 ----- eqn 4

Subtract eqn 4 from eqn 3

6a + 9y = 402

6a + 4y = 292

( - ) -------------------

5y = 110

y = 22

Thus the price of 1 youth ticket is $ 22

3 0

3 years ago

[10 points] A manufacturer wants to design an open box having a square base and a surface area of 108 square inches. What dimens

MissTica

Answer:

6 inches square by 3 inches high

Step-by-step explanation:

For a given surface area, the volume of an open-top box is maximized when it has the shape of half a cube. If the area were than of the whole cube, it would be 216 in² = 6×36 in².

That is, the bottom is 6 inches square, and the sides are 3 inches high.

_____

Let x and h represent the base edge length and box height, respectively. Then we have ...

x² +4xh = 108 . . . . box surface area

Solving for height, we get ...

h = (108 -x²)/(4x) = 27/x -x/4

The volume is the product of base area and height, so is ...

V = x²h = x²(27/x -x/4) = 27x -x³/4

We want to maximize the volume, so we want to set its derivative to zero.

dV/dx = 0 = 27 -(3/4)x²

x² = (4/3)(27) = 36

x = 6

h = 108/x² = 3

The box is 6 inches square and 3 inches high.

_____

Comment on maximum volume, minimum area

In the general case of an open-top box, the volume is maximized when the cost of the bottom and the cost of each pair of opposite sides is the same. Here, the "cost" is simply the area, so the area of the bottom is 1/3 the total area, 36 in².

If the box has a closed top, then each pair of opposite sides will have the same cost for a maximum-volume box. If costs are uniform, the box is a cube.

7 0

3 years ago