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3 years ago

REALLY NEED HELP WITH THIS!!!

Mathematics

1 answer:

koban [17]3 years ago

4 0

Answer:

Step-by-step explanation:

Solve the equation

Area =1/2(heightxbase)

27=1/2(Xx6)

54=6x

9 =x

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Which of the following equations will result in a V-shaped graph?

lutik1710 [3]

Answer:

$y = |x - 2|$

Step-by-step explanation:

A V-shaped graph is the graph of an absolute value function.

The parent absolute value function is

$y = |x|$

Among the given options, a V-shaped graph is

$y = |x - 2|$

This graph is obtained by shifting the parent absolute value function 2 units right.

The correct option is A

5 0

4 years ago

statistical models predict that price p( in dollars) of a new smartphone will change according to the function p=900-4t^2. where

miskamm [114]

You are given the function $p=900-4t^2.$

Express t:

$4t^2=900-p,\\\\t^2=\dfrac{900-p}{4},\\\\t=\sqrt{\dfrac{900-p}{4}}.$

This expression gives the month t in terms of the price p.

5 0

4 years ago

Read 2 more answers

20 POINTS!!!! write an example of an equation with variables on each side. state the steps you would use to isolate the variable

DENIUS [597]

3y + 2 = 5(y - 6) this is what i found i hope it helps

5 0

3 years ago

If LaTeX: m\angle ABF=8s-6m ∠ A B F = 8 s − 6 and LaTeX: m\angle ABE=2\left(s+11\right)m ∠ A B E = 2 ( s + 11 ), find LaTeX: m\a

kolbaska11 [484]

Answer:

Step-by-step explanation:

Given the angles ∠ABF=8s-6, ∠ABE = 2(s + 11), we are to find the angle ∠EBF. The following expression is true for the three angles;

∠ABF = ∠ABE + ∠EBF

Substituting the given angles into the equation to get the unknown;

8s-6 = 2(s + 11)+ ∠EBF

open the parenthesis

8s-6 = 2s + 22+ ∠EBF

∠EBF = 8s-6-2s-22

collect the like terms

∠EBF = 8s-2s-22-6

∠EBF = 6s-28

factor out the common multiple

∠EBF = 2(3s-14)

<em>Hence the measure of angle ∠EBF is 2(3s-14)</em>

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%28sinx%5E%7B2%7D%20theta%29%5Cfrac%7Bx%7D%7By%7D%281%2Bcostheata%29" id="TexFormula1" title="

beks73 [17]

The result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

<h3>How to evaluate the expression?</h3>

The expression is given as:

$\sin^2(\theta) * (1 + \cos(\theta))$

Express $\sin^2(\theta)$ as $1 - \cos^2(\theta)$ .

So, we have:

$\sin^2(\theta) * (1 + \cos(\theta)) = (1- \cos^2(\theta)) * (1 + \cos(\theta))$

Open the bracket

$\sin^2(\theta) * (1 + \cos(\theta)) = 1 + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Express 1 as cos°(Ф)

$\sin^2(\theta) * (1 + \cos(\theta)) = cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Hence, the result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Read more about trigonometry expressions at:

brainly.com/question/8120556

#SPJ1

3 0

3 years ago

REALLY NEED HELP WITH THIS!!!​

REALLY NEED HELP WITH THIS!!!