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garri49 [273]
1 year ago
9

Maya is solving the quadratic equation by completing the square.

Mathematics
1 answer:
kvasek [131]1 year ago
6 0

Step-by-step explanation:

factor 4 out of the variable terms, as this helps.

but my approach is simply to define the target and then calculate "backwards".

we want to find

(ax + b)² = a²x² + 2abx + b²

and now we compare with the original equation :

a²x² = 4x²

a² = 4

a = 2

2abx = 16x

2×2×bx = 16x

4b = 16

b = 4

b² = 16, but we have only 3, so we need to subtract 16-3 = 13 from the completed square.

so, our equation is

(2x + 4)² - 13 = 0

(2x + 4)² = 13

2x + 4 = sqrt(13)

2x = sqrt(13) - 4

x = sqrt(13)/2 - 2

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bazaltina [42]

The force acting on a body of mass 0.8 kg is F = 7.84 kg-m-s⁻² or F = 7.84 N

<h3>What is mass?</h3>

A tangible body's mass is the amount of matter it possesses. It's also a metric of inertial or the resistance to velocity when a net force is exerted.

We have:

The mass of the body m = 0.8 kg

As we know,

F = mg

F is the force acting on the body and g is the acceleration due to gravity.

g = 9.8 m-s⁻²

F = (0.8)(9.8)

F = 7.84 kg-m-s⁻²

or

F = 7.84 N

Thus, the force acting on a body of mass 0.8 kg is F = 7.84 kg-m-s⁻² or F = 7.84 N

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Step-by-step explanation:



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3 years ago
What is the GCF of 44 and 110?
TEA [102]
In order to find the GCF of these two numbers we need to list all their factors and find the first common one so.

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The Hickory Stick has a selection of 3 meats and 6 vegetables. How many different selections of one meat and one vegetable are p
valentina_108 [34]

The <u>different</u> selections of<u> one</u> meat and <u>one</u> vegetable are possible are 18 selections.

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Also, the number of ways we can select <u>one </u>vegetable out of 6 is ⁶C₁ = 6.

So, the total number of selections of <u>one</u> meat and <u>one</u> vegetable is ³C₁ × ⁶C₁ = 3 × 6

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So, the <u>different</u> selections of<u> one</u> meat and <u>one</u> vegetable are possible are 18 selections.

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