The force acting on a body of mass 0.8 kg is F = 7.84 kg-m-s⁻² or F = 7.84 N
<h3>What is mass?</h3>
A tangible body's mass is the amount of matter it possesses. It's also a metric of inertial or the resistance to velocity when a net force is exerted.
We have:
The mass of the body m = 0.8 kg
As we know,
F = mg
F is the force acting on the body and g is the acceleration due to gravity.
g = 9.8 m-s⁻²
F = (0.8)(9.8)
F = 7.84 kg-m-s⁻²
or
F = 7.84 N
Thus, the force acting on a body of mass 0.8 kg is F = 7.84 kg-m-s⁻² or F = 7.84 N
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Answer: The correct answer is 97
Step-by-step explanation:
In order to find the GCF of these two numbers we need to list all their factors and find the first common one so.
44: 1,2,4,11,22,44
110, 1,2,5,10,11,22,55,110
Since 22 is the highest number that both share and its common, that would be your answer. Answer: 22.
The <u>different</u> selections of<u> one</u> meat and <u>one</u> vegetable are possible are 18 selections.
Since the Hickory Stick has a selection of 3 meats and 6 vegetables, the number of ways we can select <u>one </u>meat out of 3 is ³C₁ = 3.
Also, the number of ways we can select <u>one </u>vegetable out of 6 is ⁶C₁ = 6.
So, the total number of selections of <u>one</u> meat and <u>one</u> vegetable is ³C₁ × ⁶C₁ = 3 × 6
= 18 selections
So, the <u>different</u> selections of<u> one</u> meat and <u>one</u> vegetable are possible are 18 selections.
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Answer:
23 cents (.23)
Step-by-step explanation:
2.30 divided by 10