Maya is solving the quadratic equation by completing the square.
1 answer:
Step-by-step explanation:
factor 4 out of the variable terms, as this helps.
but my approach is simply to define the target and then calculate "backwards".
we want to find
(ax + b)² = a²x² + 2abx + b²
and now we compare with the original equation :
a²x² = 4x²
a² = 4
a = 2
2abx = 16x
2×2×bx = 16x
4b = 16
b = 4
b² = 16, but we have only 3, so we need to subtract 16-3 = 13 from the completed square.
so, our equation is
(2x + 4)² - 13 = 0
(2x + 4)² = 13
2x + 4 = sqrt(13)
2x = sqrt(13) - 4
x = sqrt(13)/2 - 2
You might be interested in
Let's start by moving all like terms to their own sides:
-18 = -3x + 6
3x = 6 + 18
3x = 24
x = 8
The answer to this is 50 x 10 the 9th power.
Hope this helps :)
So, since we have a cubic equation with 4 terms, the first thing we should try is factoring by grouping, so:
Now that we've factored our equation, we can use ZPP and break it up:
So, our solutions are:
Commutative i believe <span />
The answer is 4/9 or 0.44444
