8r.) Find the amount A in an account after t years given the following conditions.
2 answers:
You can rewrite the differential equation as

This last expression looks like the one you describe. If you solve for A instead of t, you get

This is the same as your other answer.
dA/dt = 0.02A
dA/A = 0.02dt
integrating left n right
lnA = 0.02t + C where C is a constant
at t=0, A=4000
C=ln4000
lnA = 0.02t + ln4000
0.02t = lnA-ln4000
t = ln(A/4000) / 0.02
t = 40ln(A/4000)
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Step-by-step explanation:
I got it right on khan academy
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12x =48 (Divide 48 by 12)
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