Using the normal distribution, it is found that 95.65% of full term newborn female infants with a head circumference between 31 cm and 36 cm.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean 
and standard deviation 
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
The proportion of full term newborn female infants with a head circumference between 31 cm and 36 cm is the <u>p-value of Z when X = 36 subtracted by the p-value of Z when X = 31</u>, hence:
X = 36:
Z = 1.83
Z = 1.83 has a p-value of 0.9664.
X = 31:
Z = -2.33
Z = -2.33 has a p-value of 0.0099.
0.9664 - 0.0099 = 0.9565.
0.9565 = 95.65% of full term newborn female infants with a head circumference between 31 cm and 36 cm.
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Answer:
D. 0.925x + 0.88y = 0.91(x + y)
Step-by-step explanation:
The important point to remember is that the total mass of pure silver is the same on each side of the equation.
0.925x = mass of pure silver in first alloy
0.88 y = mass of pure silver in second alloy
The final alloy has a mass of (x + y) g and is 91 % pure silver, so
0.925x + 0.88y = 0.91(x + y)
Answer:
See explanation below
Step-by-step explanation:
Given the ratio between two groups to be 3:7
Total ratio = 3+7 = 10
Total sweet shared = 30sweets
For the group with ratio of 3;
Share = 3/10×30
Share = 3×3
Share = 9 sweet
For the group with ratio of 5
This share = 7/10×30
This share = 7×3
This share = 21sweet
If you want to round 98.155 to the nearest tenth, it is 98.2.
The 1 is in the tenths place.
If the number to the right of it is 5 or more, round up.
If the number to the right of it is 4 or less, round down.
In this case, you round the digit in the tenths place up because the digit in the <em>hundredths</em> place is 5+.
Given:
pool length : 10 yards
pool width : 8 yards
Area = 10 yds * 8 yds = 80 yd²
(10 + 2x)(8 + 2x) = 120
10(8 + 2x) + 2x(8+2x) = 120
80 + 20x + 16x + 4x² = 120
4x² + 36x + 80 - 120 = 0
4x² + 36x - 40 = 0
4(x² + 9x - 10) = 0
4(x + 10)(x - 1) = 0
x + 10 = 0
x = -10
x - 1 = 0
x = 1
the width of the deck is 1 yard
