Answer:
A. 1/16
Explanation:
If we break the dihybrid cross of AaBb X AaBb into individual monohybrid crosses:
Aa X Aa :
A a
A AA Aa
a Aa aa
1/4 of the progeny will be homozygous for dominant allele (AA)
Similarly, in cross Bb X Bb 1/4 of the progeny will be homozygous for dominant allele (BB)
Hence, in cross AaBb X AaBb:
1/4 * 1/4 = 1/16 will be homozygous for both the dominant alleles.
Answer: observe the feeding behaviors of gulls
