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STALIN [3.7K]
3 years ago
15

What is 6/10 divided by 2/5

Mathematics
2 answers:
yarga [219]3 years ago
8 0
The equation becomes:

6 5
— / —
10 2

because you have to flip the second fraction when dividing.

Cross multiply:

6 5
— / —
10 2

=

3 1
— / —
2 1

Final Answer:
3/2
babunello [35]3 years ago
3 0

Answer:3/2

Step-by-step explanation:

6/10 ➗ 2/5

6/10 x 5/2

(6x5)/(10x2)

30/20=3/2

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19. During a 2 3/4 hour assembly, each speaker spoke for 1/4 of an hour. How many speakers were there?​
atroni [7]

Answer:

11 speakers

Step-by-step explanation:

2 3/4 ÷ 1/4

11/4 ÷ 1/4

11/4 x 4/1 = 44/4 = 11

6 0
3 years ago
Read 2 more answers
assume that when adults with smartphones are randomly selected, 44% use them in meetings or classes. If 10 adult smartphones use
tensa zangetsu [6.8K]

Solution: The given random experiment follows Binomial distribution with n=10,p=0.44

Let X be the number of adults who use their smartphones in meetings or classes.

Therefore, we have to find:

P(X

We know the binomial model is:

P(X=x)=\binom{n}{x} p^{x} (1-p)^{n-x}

\therefore P(X

                       =\binom{10}{0}0.44^{0}(1-0.44)^{12-0}+\binom{10}{1}0.44^{1}(1-0.44)^{10-1}+\binom{10}{2}0.44^{2}(1-0.44)^{10-2}

                       =1 \times 1 \times 0.0030 + 10 \times 0.44 \times 0.0054 + 45 \times 0.1936 \times 0.009672

                       =0.0030+0.0238+0.0843

                       =0.1111

Therefore, the probability that fewer than 3 of them is 0.1111

7 0
3 years ago
2 y - 8 / 3 equals a + 3 B / 4 solving for y
zhuklara [117]
-2x+5
I am pretty sure
4 0
3 years ago
8 circles and 10 triangles.
madreJ [45]

Answer:

2:5

Step-by-step explanation:

Because if we look 8:20 can be turned into 8/20 and if we simply we got 2/5 and turn it into 2:5

8 0
3 years ago
3. Write a similarity statement and state the scale<br> factor for the triangles.
ivann1987 [24]

Answer:

AA SIMILARITY statement

SSS similarity statement is also possible.

Step-by-step explanation:

In \:  \triangle CBA  \: and \:  \triangle TVU \\  \angle B \cong \angle V... (given) \\\angle A \cong \angle U... (given) \\\therefore \triangle CBA \sim \triangle TVU... (By AA\: Postulate)  \\

5 0
3 years ago
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