I think it's D + .2 = ? i'm not sure but it might be something like that
Answer:
1000000 = 1 MLN CODES
Step-by-step explanation:
According the terms of the problems the code has 6 digits or has 6 positions.
At 1st position any of 10 digits (0,1,2,3,4,5,6,7,8 or 9 ) can put
The digits can repeated, so at position 2 any of 10 difits can put.
At position 3 again any of 10 digits can put and similarly for each of next positions can be put any of 10 digits.
So each position of the code has 10 possible variants.
To find the total number of possible codes we have to multiply the number of variants for each position to each other.
N=10*10*10*10*10*10= 10^6=1 000 000
A
Sq rt each side you get
X+3= +-8
X+3=8
-3. -3
X=5
X+3=-8
-3. -3
X=-11
