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Shtirlitz [24]
3 years ago
7

Can anyone​ please help me step by step on how to solve this problem?

Mathematics
2 answers:
Sholpan [36]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

The volume (V) of a cuboid is calculated using the formula

V = lbh ( l is length, b is breadth and h is height )

Equate the product of the dimensions to 374

2(x + 3)(x + 9) = 374 ( divide both sides by 2 )

(x + 3)(x + 9) = 187 ← expand factors on left side

x² + 12x + 27 = 187 ( subtract 187 from both sides )

x² + 12x - 160 = 0 ← in standard form

Factor by considering the factors of the constant term (- 160) which sum to give the coefficient of the x- term (+ 12)

The factors are + 20 and - 8, hence

(x + 20)(x - 8) = 0

Equate each factor to zero and solve for x

x + 20 = 0 ⇒ x = - 20

x - 8 = 0 ⇒ x = 8

solutions are x = - 20, x = 8

However x > 0 ⇒ x = 8 and

x + 3 = 8 + 3 = 11

x + 9 = 8 + 9 = 17

Dimensions are 2cm, 11 cm, 17 cm

sergejj [24]3 years ago
6 0

you have to make an equation for the volume

volume = l × w × d

subsitute values given

2 × (x+3) × (x+9) = 374

multiply (x+3) and (x+9) first

2 × (x^2+12x+27) = 374

multiply left side by 2

2x^2 + 24x + 54 = 374

everything is divisible by 2 so you can divide by 2 on both sides to make it simpler

x^2 + 12x + 27 = 187

minus 187 on both sides to set equation equal to 0

x^2 + 12x - 160 = 0

factorise with two factors of -160 that add up to give 12

(x + 20)(x - 8) = 0

x + 20 = 0

x - 8 = 0

therefore

<em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>8</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>-</u></em><em><u>2</u></em><em><u>0</u></em>

<em>h</em><em>o</em><em>w</em><em>e</em><em>v</em><em>e</em><em>r</em><em>,</em><em> </em><em>x</em><em> </em><em>c</em><em>a</em><em>n</em><em>n</em><em>o</em><em>t</em><em> </em><em>b</em><em>e</em><em> </em><em>-</em><em>2</em><em>0</em><em> </em><em>a</em><em>s</em><em> </em><em>i</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>r</em><em>e</em><em>p</em><em>r</em><em>e</em><em>s</em><em>e</em><em>n</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>l</em><em>e</em><em>n</em><em>g</em><em>t</em><em>h</em><em>s</em><em>,</em><em> </em><em>w</em><em>h</em><em>i</em><em>c</em><em>h</em><em> </em><em>c</em><em>a</em><em>n</em><em>n</em><em>o</em><em>t</em><em> </em><em>b</em><em>e</em><em> </em><em>n</em><em>e</em><em>g</em><em>a</em><em>t</em><em>i</em><em>v</em><em>e</em><em>.</em>

<em>s</em><em>o</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>solution</em><em> </em><em>we</em><em> </em><em>must</em><em> </em><em>use</em><em> </em><em>later</em><em> </em><em>on</em><em> </em><em>is</em><em> </em><em>8</em><em>.</em>

<em>the</em><em> </em><em>dimensions</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>cuboid</em><em> </em><em>are</em><em> </em>

<em>2</em>

<em>x</em><em> </em><em>+</em><em> </em><em>3</em><em> </em>

<em>x</em><em> </em><em>+</em><em> </em><em>9</em>

we know the value of x which is 8 so we substitute this.

dimensions:

2

8 + 3

8 + 9

therefore the dimensions of the cuboid are:

<em><u>2</u></em><em><u>cm</u></em><em><u>,</u></em><em><u> </u></em><em><u>1</u></em><em><u>1</u></em><em><u>cm</u></em><em><u>,</u></em><em><u> </u></em><em><u>1</u></em><em><u>7</u></em><em><u>cm</u></em>

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