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Sati [7]
3 years ago
9

Prepare a 1.00 L of a 0.25 M solution of sodium carbonate. Determine the amount of sodium carbonate needed in correct significan

t figures.
Chemistry
1 answer:
AleksandrR [38]3 years ago
4 0

Answer:

Mass = 26.50 g

Explanation:

Given data:

Mass of sodium carbonate = ?

Molarity of solution = 0.25 M

Volume of solution = 1.00 L

Solution:

Molarity = number of moles / volume in litter

0.25 M = number of moles / 1.00 L

Number of moles = 0.25 M × 1.00 L

Number of moles = 0.25 mol

Mass:

Mass = number of moles × molar mass

Mass = 0.25 mol × 106 g/mol

Mass = 26.50 g

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A compound is 53.31% c, 11.18% h, and 35.51% o by mass. what is its empirical formula?
Alexus [3.1K]
<span>Your final answer would be C4H10O2, which equals 90amu</span>
3 0
4 years ago
Does the bowling ball have more potential energy or kinetic energy as it is halfway through its fall? Why?
ahrayia [7]

Answer:

more kinetic

Explanation:

I think the kinetic energy is 75 percent while the potential energy is 25 percent

5 0
4 years ago
In the laboratory a student finds that it takes 44.0 Joules to increase the temperature of 10.6 grams of solid zinc from 24.9 to
BaLLatris [955]

Answer:

The specific heat of zinc is 0.361 J/g°C

Explanation:

<u>Step 1:</u> Data given

44.0 J needed

Mass of solid zinc = 10.6 grams

Initial temperature = 24.9 °C

Final temperature = 36.4 °C

<u>Step 2</u>: Calculate the specific heat of zinc

Q = m*c*ΔT

⇒ with Q = heat (in Joule) = 44.0 J

⇒ with m = the mass of the solid zinc = 10.6 grams

⇒ with c = the specific heat of the zinc = TO BE DETERMINED

⇒ with ΔT = The change in temperature = T2-T1 = 36.4 °C - 24.9 °C = 11.5 °C

44.0 J = 10.6 grams * c * 11.5°C

c = 44.0 J / (10.6g * 11.5 °C)

c = 0.361 J/g°C

The specific heat of zinc is 0.361 J/g°C

7 0
4 years ago
How many moles of KOH are required to produce 4.79 g K3PO4 according to the following reaction? 3KOH + H3PO4 -----&gt; K3PO4 + 3
8_murik_8 [283]

Answer:

0.677 moles

Explanation:

Take the atomic mass of K = 39.1, O =16.0, P = 31.0

no. of moles = mass / molar mass

no. of moles of K3PO4 used = 4.79 / (39.1x3 + 31 + 16x4)

= 0.02256 mol

From the equation, the mole ratio of KOH : K3PO4 = 3 :1,

meaning every 3 moles of KOH used, produces 1 mole of K3PO4.

So, using this ratio, let the no. of moles of KOH required to be y.

\frac{3}{1} =\frac{y}{0.02256} \\

y = 0.02256 x3

y = 0.0677 mol

If you don't find exactly 0.677 moles as one of the options, go for the closest one. A very slight error may occur because of taking different significant figures of atomic masses when calculating.

5 0
3 years ago
What increases OH ions​
hram777 [196]

Answer:

A base.

Explanation:

Basic solutions give OH- ions.

7 0
4 years ago
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