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3 years ago

How many total electrons can the d orbital hold

Chemistry

2 answers:

liberstina [14]3 years ago

7 0

Answer:

10 electrons

Explanation:

The d sublevel has 5 orbitals, so can contain 10 electrons max. And the 4 sublevel has 7 orbitals, so can contain 14 electrons max. In the picture below, the orbitals are represented by the boxes. You can put two electrons in each box.

polet [3.4K]3 years ago

6 0

Answer:

Explanation:

you're welcome

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A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal

bija089 [108]

Answer:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 25.0 L

V₂ = ?

P₁ = 2575 mm Hg

Also, P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}$

$\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}$

Solving for V₂ , we get:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

4 0

4 years ago

An experiment requires that each student use an 8.5 cm length of magnesium ribbon. How many students can do the experiment if th

melisa1 [442]

570/8.5=67.0 58... you only have to take the natural part, si the answer is 67 students

7 0

3 years ago

Read 2 more answers

What is the density of a rectangular block that has a mass of 500 grams and a volume of 50cm^3

oee [108]

Density = mass / volume

D = 500 g / 50 cm³

D = 10 g/cm³

hope this helps!

6 0

4 years ago

A chemist has one solution that is 20% salt and a second solution that is 45% salt. How many liters of each should be used in or

Free_Kalibri [48]

Answer:

8 liters of the first salt solution and 12 liters of the second salt solution is needed to get 20L of a solution that is 30% salt

Explanation:

Let x represent the liters of the first salt solution

Let y represent the liters of the second salt solution

x + y= 20......equation 1

x= 20-y

The first solution is 20% salt and the second solution is 45% salt

20/100x + 45/100 y= 30/100 × 20

0.2x + 0.45y= 0.3×20

0.2x + 0.45y= 6............equation 2

Substitute 20-y for x in equation 2

0.2(20-y) + 0.45y= 6

4-0.2y+ 0.45y= 6

4 + 0.25y= 6

0.25y= 6-4

0.25y= 2

y= 2/0.25

y= 8

Substitute y for 8 in equation 1

x + y= 20

x + 8=20

x= 20-8

x= 12

Hence 8 liters of the first salt solution and 12 liters of the second salt solution is needed to get 20L of a solution that is 30% salt.

4 0

3 years ago

There is a 30 g sample of Be-11. It has a half-life of about 14 seconds.How much will be left after 28 seconds?A.3.75 gB.7.5 gC.

pshichka [43]

Answer:

After 28 sec 7.5 grams of Be will be left

Explanation:

Given data:

Total amount of Be = 30 g

Half life of Be = 14 sec

Mass left after 28 sec = ?

Solution:

First of all we will calculate the number of half lives in 28 sec.

Number of half lives = T elapsed / half life

Number of half lives = 28 sec / 14 sec

Number of half lives = 2

AT time zero = 30 g

At first half life = 30 g/2 = 15 g

At second half life = 15 g/ 2 = 7.5 g

So after 28 sec 7.5 grams of Be will be left.

5 0

4 years ago