1.1 moles of C10H8 is the limiting reagent in the reaction between reaction C10H8 and O2
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C10H8 + 12O2 ----> 10CO2 + 4H2O
C10H8 is the limiting reagent since 1.1 moles of C10H8 is totally consumed during the reaction
i think the answer is COS2 tell me if im right or wrong
2.4 mol NaSO2 × (6.02×10^23) f.units ÷ 1 mol
=1.44480000×10^25
Approximately 1.4×10^25, if you use sig.figs.
Explanation:
(1.) A hydrophobic compound is defined as the compound that does not dissolve in water and they contain no charge. Hydrophobic compounds are generally organic in nature.
- As a result, there occurs no interaction between an ionic compound and hydrophobic compound. This is because ionic solvents or compounds are charged species and hydrophobic compounds do not contain any charge.
Hence, there occurs no interaction between the two.
- Whereas lower is the dielectric constant of a solvent, less polar it will be in nature. Hence, smaller is the value of a dielectric constant more readily and easily it is able to dissolve a hydrophobic compound.
- On the other hand, higher is the value of dielectric constant more polar the substance will be in nature. As a result, hydrophobic substance will not dissolve in high dielectric constant solvents and polar solvents such as water.
(2.) Pyrogen is defined as any substance that is able to cause fever. Bacterial pyrogens are endotoxins and exotoxins.
And, if both of these toxins are not removed from the body then they tend to interact with the mechanism of drug interaction and hence, these lead to unexpected side effects.
Therefore, the statement if formulating an aqueous solution for parenteral administration, filtered and sterile pyrogen free water must be used, is true.
All matter (solid, liquid or gas) has a definite shape and occupies a specific volume.
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Hope it helps...</h2>
