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alexandr1967 [171]
4 years ago
9

Alex runs up a staircase with n steps, and can hop either 1, 2, or 3 steps at a time. Count how many possible ways the child can

run up the stairs. solution?
Mathematics
1 answer:
MArishka [77]4 years ago
8 0

Answer:

There are 4 possible ways

Step-by-step explanation:

Data provided in the question:

Alex can hop in 1 steps, 2 steps, or 3 steps at a time.

From the above data it can be concluded that at a single maximum 3 steps can be run at a time

thus,

for running 3 steps at a time from the above data, we can have

with 1 step only : {1 , 1 , 1}

with 1 step first and 2 steps : {1 , 2}

with 2 steps first and then the 1 step: {2 , 1}

and 3 steps at once : {3}

thus, we have 4 possible ways to run up the stairs keeping the above condition.

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The square with side length 2 cm is dilated by a scale factor of 7/3 is the dilated image larger or smaller than the original im
qwelly [4]
Length of square side= 2 cm
Dilation factor= 7/3
Simplify 7/3= 2.33
Apply the dilation factor:
Length of side= 2.33 x 2 = 4.67 cm
As the length of the side of the square is increased in length, which means the dilated image is larger than the original image.

Answer: Larger than then original. 
8 0
3 years ago
student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te
alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0
3 years ago
A dealer paid $10,000 for a boat at an auction. At the dealership, the sales person sold the boat for 30% more than the auction
Margaret [11]
The answer is B, $10,000 is given and is not a variable that can be changed, since there are 150 band students raising money it would be 150x, and the 30,000 is the goal of the fundraiser
8 0
3 years ago
Is anybody able to help me get number ten? (Geometry)
Nikitich [7]

Answer:

Aha..our nemesis problem. :)

The area is 129.90 ft ^2.

Step-by-step explanation:

First, use a 30-60-90 triagle to find the apothem.

5\sqrt{3} =8.66\\8.66*5=43.30\\43.30/2=21.65\\

That is the area of 1 triangle. There are 6 of them in a hexagon, so multiply that number by 6:

21.65*6=129.90 ft ^2

Have a great day!

6 0
3 years ago
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d1i1m1o1n [39]

Answer:

Please post a picture with higher quality, I cannot read this one

Step-by-step explanation:

4 0
3 years ago
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