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Anna11 [10]
3 years ago
6

Myra saved $15 a month for 18 months. She bought a book for $46.50 and a tennis racquet for $129.95. How much does she have left

? A. $93.55 B. $140.05 C. $186.55
Mathematics
1 answer:
Elis [28]3 years ago
7 0

Answer:

A

Step-by-step explanation:

15*18=270.

270-46.50=223.5

223.5-129.95=93.55.

A. $93.55

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As 9 hundreds is 9 thousand
s2008m [1.1K]
9 hundreds=900 9 thousands=9,000
6 0
3 years ago
MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
ioda

Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

                                 l^{2} + l^{2} + l^2   =  64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}

                       

                                                 

7 0
3 years ago
The city of Omaha decided to build a new parking garage in hopes of luring more people to the Old Market district.The city will
dimulka [17.4K]

Answer:

Given:

Mean, u = 135

Sample size, n = 42

Sample mean, x' = 126

Standard deviation = 16

Significance level = 0.05

1) The null and alternative hypotheses:

H0 : u = 135 (the revenue per day is $135)

H1 : u < 135 (the revenue per day is less than $135)

2) In this case, we have a left tailed test.

Let's use the formula:

= \frac{x' - u}{s/ \sqrt{n}} = \frac{126 - 135}{16 / \sqrt{42}} = -3.645

t = - 3.645

Critical value: at a significance level of 0.05, left tailed test,

tcritical = -1.683

We reject null hypothesis, H0, since t calculated, -3.645 is less than tcritical, -1.683.

3) Given, a = 0.05, df = 41, left tailed test,

t-value = 2.02

For the corresponding confidence interval, we have:

CI = (x' - \frac{t * \sigma}{\sqrt{n}}, x' + \frac{t * \sigma}{\sqrt{n}})

CI = (126 - \frac{2.02 * 16}{\sqrt{42}}, 126 + \frac{2.02 * 16}{\sqrt{42}})

CI = (121.014, 130.986)

4) Conclusion:

We reject the estimated potential revenue advised by the consultant, H0, as it is too high, because the t-calculated falls in rejection region(i.e, less than critical value), also the upper limit of the confidence interval is less than $135.

5 0
2 years ago
After each charging, a battery is able to hold only 97% of the charge from the previous charging. The battery was used for 18 ho
Cerrena [4.2K]

Answer:

The total nuber of hours that the battery can be used over its lifetime is 600.

Step-by-step explanation:

We use an infinite geometric series to solve this question.

The sum of all values of an infinite geometric series is given by the following equation:

S = \frac{a_{1}}{1 - r}

In which a_{1} is the first term and r is the common ratio.

After each charging, a battery is able to hold only 97% of the charge from the previous charging.

This means that r = 0.97

The battery was used for 18 hours on its first charge before it had to be recharged.

This means that a_{1} = 18

What is the total number of hours the battery can be used over its lifetime?

S = \frac{18}{1 - 0.97} = 600

The total nuber of hours that the battery can be used over its lifetime is 600.

7 0
3 years ago
1. Identify the vertex and the y-intercept of the graph of the function y=-2(x+ 2)+2.
KATRIN_1 [288]

Answer:

Please let me know if your quadratic is y=-2(x+2)^2+2.

And if so your vertex is (-2,2) and your y-intercept is (0,-6)

Step-by-step explanation:

It says vertex so I'm thinking you meant y=-2(x+2)^2+2.  Please correct me if I'm wrong.

The vertex form of a quadratic is y=a(x-h)^2+k.  It is called that because it tells you the vertex (h,k).

So if you compare the two forms you should see -h=2 while k=2.

-h=2 implies h=-2.

So the vertex is (h,k)=(-2,2).

To find the y-intercept, set x=0 and find y.

y=-2(0+2)^2+2

y=-2(2)^2+2

y=-2(4)+2

y=-8+2

y=-6

So the y-intercept is (0,-6).

7 0
3 years ago
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