Yup your right ( i’m just writing here so it lets me send it)
Try this solution:
D(f): √(2-x)≥0; ⇔ 2-x≥0; ⇔ x≤2 or x∈(-∞; 2].
.300 + .060 + .008
You would break each number's place value down and add them in a line, in decimals, you would do the exact same.
Answer: 2/3
Step-by-step explanation:
Hope this helps
Answer:
#1) A. 4; #2) A. periodic; about 6; #3) B. not periodic; #4) C. 2; 0.5; #5) A. 0.05 seconds; 4.5.
Explanation:
#1) The period of a function is essentially the amount of time it takes for the function to start all over and repeat itself. In this function, at t = 0 the graph is at 1; it curves up, back down and begins again at y=1 when t=4. This means the period goes from t=0 to t=4, so it is 4.
#2) Looking at the left side of the graph, specifically the peak at (-5, 2), we see the same peak at about (1, 2). Following the graph after that we can see that it does indeed repeat itself; this means the period goes from t= - 5 to t = 1, so it is 6.
#3) This function never repeats, so it is not periodic.
#4) This function repeats when it reaches t=2, so 2 is the period. The amplitude is the distance from the center line (of the graph, not the x-axis) to the peak. The center line would be located at about y=0.5; the peaks are at y=-1. This means the amplitude is 0.5.
#5) This function repeats every 0.05 seconds. In this case, the center line is the x-axis; the distance from it to any peak is 4.5, so 4.5 is the amplitude.
