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Sedaia [141]
3 years ago
5

Sea level is considered to be 0 feet. A probe released at sea level dropped at a constant rate for 3.25 minutes, reaching an ele

vation of −35.75 feet relative to sea level.
What was the probe's elevation relative to sea level after the first minute?
Mathematics
2 answers:
Anvisha [2.4K]3 years ago
6 0
The probe dropped 11 feet per minute, therefore, it dropped 11 feet in the first minute
Kruka [31]3 years ago
6 0

Answer:

-11

Step-by-step explanation:

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Find the surface area of a right square pyramid if the area of the base is 3636 cm squaredcm2 and the height of the pyramid is 6
Bond [772]
The surface area is 1203cm good luck on your homeworek
5 0
3 years ago
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.. 10 is what percent of 7? Round the nearest whole percent.
romanna [79]

Answer:

143%

Step-by-step explanation:

\frac{10}{7}x100=142.9%=143%

7 0
3 years ago
Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x
Savatey [412]
The polynomial remainder theorem states that the remainder upon dividing a polynomial p(x) by x-c is the same as the value of p(c), so to find p(-10) you need to find the remainder upon dividing

\dfrac{2x^3+14x^2-58x}{x+10}

You have

..... | 2 ...  14  ... -58
-10 |    ... -20  ... 60
--------------------------
..... | 2 ...  -6  ....  2

So the quotient and remainder upon dividing is

\dfrac{2x^3+14x^2-58x}{x+10}=2x-6+\dfrac2{x+10}

with a remainder of 2, which means p(-10)=2.
5 0
3 years ago
Beth has 250 comic books in her collection. She begins to sell 20 of them each week. Martin has 80 comic books in his collection
guapka [62]

Answer:

250 - 20 < 80 + 15x

Step-by-step explanation:

Given that

Beth has 250 books and 20 books sold each week

While on the other hand, Martin has 80 books and sell 15 books each week

Let us assume each week be x

Now the equations are  

Beth         250 - 20x            

Martin       80 + 15 x

Now the inequality would be

250 - 20 < 80 + 15x

8 0
3 years ago
A typical running track is an oval with 74-m-diameter half circles at each end. a runner going once around the track covers a di
denpristay [2]

Answer:

Her centripetal acceleration during the turn at each end of the track is 0.432\, \frac{m}{s^{2}}

Step-by-step explanation:

Total distance covered in one round , D= 400 m

Time taken to cover one round , T = 1 min 40 s = 100 sec

Speed of runner , V=\frac{D}{T}=\frac{400}{100}\, \frac{m}{s}= 4.0\, \frac{m}{s}

Now centripetal acceleration is given by

a_c=\frac{V^{2}}{R}

where V= 4.0\frac{m}{s}

Radius, R= \frac{Diameter}{2}=\frac{74}{2}m=37\, m

\therefore a_c=\frac{4^{2}}{37}\, \frac{m}{s^{2}}=0.432\, \frac{m}{s^{2}}

Thus her centripetal acceleration during the turn at each end of the track is 0.432\, \frac{m}{s^{2}}

4 0
3 years ago
Read 2 more answers
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